How to get network range with CIDR

Hello,

I have below 2 CIDR IP range and would like to get 4 network range of /24 each. How can I get it?

10.253.0.0/19
10.253.32.0/19

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Thanks!
beer9Asked:
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Zephyr ICTCloud ArchitectCommented:
What are your requirements exactly?

You already have a large range, you can just divide them into separate /24 subnets ...

10.253.0.0/24
10.253.1.0/24
10.253.2.0/24
10.253.3.0/24
and so on until 10.253.31.0/24

Same goes for the other range
10.253.32.0/24
10.253.33.0/24
10.253.34.0/24
10.253.35.0/24
and so until 10.253.63.0/24

Of course you can just take 4 /24 subnets and re-divide the leftover into larger or even smaller subnets...
matrix8086Commented:
The result is 32 network ranges from each. You can choose any 4 of them. I have listed the first 4 of each range

10.253.0.0/24
10.253.1.0/24
10.253.2.0.24
10.253.3.0/24

10.253.32.0/24
10.253.33.0/24
10.253.34.0/24
10.253.35.0/24
beer9Author Commented:
I want to divide 10.253.0.0/19 and 10.253.32.0/19 only in four subnet each. How can I do that?
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matrix8086Commented:
You can not! The way things are working in IP addressing is the one we've presented
matrix8086Commented:
You can have 4 subnets for each but will be /21, not /24

10.253.0.0/21
10.253.8.0/21
...16.0/21
...24.0/21
...32.0/21
...40.0/21
...48.0/21
...56.0/21
Zephyr ICTCloud ArchitectCommented:
I'd stay with the approach I mentioned, this leaves room for much more subnets when needed...

Otherwise you'd need to really change the entire subnet and loose a lot of network... Like a /22 or a /21
Fred MarshallPrincipalCommented:
OK.  You've stated two different objectives - likely unintentionally.  It seems that dividing into 4 subnets is most likely - as in "divide the entirety into 4 subnets of equal size".  (You can have a bunch of subnets and they don't all have to be the same size).

So, matrix8086 has given the answer to that question.  
/19 has 8192 addresses.  So, 4 subnets of equal size that spans that entire address space would be 2048 addresses each or /21.

There is nothing "better" about smaller subnets unless there are other issues or requirements or constraints that you haven't mentioned.  So I would stick with /21 until more is revealed.

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