How rename part number in two tables

I have a table that contains a field for part numbers.  It is a text field.  But I need to somehow, I suppose via an update query, rename the part numbers.

Here are a few example of the current part number and the expected renamed part number:

Current                              Expected
N1100-12R05-F                 N1100-12-F     (Note that the R05 has been removed)
N1375-12X75-F                 N1375-12-F     (Note that the X75 has been removed)
N1202-12PTR4-F               N1202-12-F     (Note that the PTR4 has been removed)

So in essence, the characters following the 2nd digit after the 1st hyphen through the character prior to the 2nd hyphen have to be removed.  In some cases this would be 3 characters and in other cases it would be 4 characters.

How can I do this?
SteveL13Asked:
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SteveL13Author Commented:
I forgot to tell you the rest of the challenge.  There is a 2nd table that has the same part "numbers".  But in that table the part number may be repeated in several records.  The same new name for the part number in the 1st table has to be applied to the 2nd table part numbers.
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als315Commented:
You can add function like:
Function remove_part(ByVal Str As Variant) As Variant
Dim Arr() As String
remove_part = Str
If IsNull(Str) Or Len(Str) < 3 Then Exit Function 'String is too short
Arr = Split(Str, "-")
remove_part = Arr(0) & "-" & Left(Arr(1), 2) & "-" & Arr(2)
End Function

Open in new window

to global module and call it in any update query
UPDATE Table1 SET Table1.Field1 = remove_part([Field1]);
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SteveL13Author Commented:
Almost.  But I got an error...

"Microsoft Access can't update all the records in the update query....   440 record(s) due to key violations"

???
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SteveL13Author Commented:
A couple examples that didn't covert:

C1875-12R06-F
C1960-12R06-F
C2040-12R06-F
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als315Commented:
"Microsoft Access can't update all the records in the update query....   440 record(s) due to key violations"  -
this error is a result of your indexes. May be after conversion you get duplicate values, which are not allowed
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SteveL13Author Commented:
Yes,  You are correct.  I have to figure something else out.  But your answer is good to hang onto for future.
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