Subnetting and masks quick question

Just trying to see if I'm in the ballpark, doing my math and have a grasp of subnets correctly.
With a subnet range if you have a /21 or mask would these ranges be correct? - -
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woolmilkporcCommented:   - Hosts (2046), Network, Broadcast   - Hosts (2046), Network, Broadcast - Hosts (2046), Network, Broadcast
... - Hosts (2046), Network, Broadcast
... - Hosts (2046), Network, Broadcast

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The following is a rather simple subnet calculation method:

With a CIDR mask of /21 we have 8+8+5=21 bits for subnets and 3+8=11 bits for host/net/broadcast addresses.

Given that the first two bytes (10.50 in your example) should remain the same we have 5 bits in the third byte left for 2*2*2*2*2=32 subnets and 11 bits in the third and fourth bytes for 2*2*2*2*2*2*2*2*2*2*2=2048 hosts/net addrs/broadcast addrs.

The remaining 3 bits in byte 3 give a stepping of 2*2*2=8 (or 256-248=8, if you prefer, or 256/32=8), so our subnets are,, etc.

The lowest useable host address in a subnet is net address + 1, so our host addresses start at,, etc.

The highest useable host address in a subnet is the last address in the range - 1 (or next network address - 2, if you prefer) ,so our host addresses end at,, etc.

The broadcast addresses are the last addresses in the range (or next network address - 1, if you prefer), so the broadcast addresses are,, etc.
AMtekAuthor Commented:
thank you! much appreciated, especially with the detailed answer!
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