C++ convert string type to UnicodeString type

Given a variable of type string how can the value of this string be assigned to a UnicodeString variable ?


string s = "Hello";

UnicodeString u;

u = s ; // yields an error

Using embarcadero C++ builder XE3
Roger AlcindorAsked:
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string s = "Hello";

UnicodeString u(s.c_str());

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This is the constructor that takes an ANSI string (or better 'char*') and should do what you want to achieve. See also http://docs.embarcadero.com/products/rad_studio/delphiAndcpp2009/HelpUpdate2/EN/html/delphivclwin32/System__UnicodeString__UnicodeString.html

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evilrixSenior Software Engineer (Avast)Commented:
>> Given a variable of type string how can the value of this string be assigned to a UnicodeString variable ?
There doesn't appear to be an assignment operator for a std::string but you can easily write one yourself (and borrow from the construction that jkr has show, above). Something like this...

// works for both std::string and std::wstring
template<typename T>
UnicodeString & operator = (UnicodeString & lhs, std::basic_string<T> const & rhs)
   return lhs = UnicodeString(rhs.c_str());

// this should now work
u = s;

Open in new window

to add to above solutions:

since UnicodeString has a constructor that takes a const char * as shown by jkr, you can do

UnicodeString u = "Hello";


std::string s = "Hello";
UnicodeString u = s.c_str();

note, the second is not an assignment but an initialization what means it is only alternative syntax to the statement jkr has posted.

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Roger AlcindorAuthor Commented:
evilrix's solution looks elegant but compiles with the following error :
[BCC32 Error] Unit1.h(16): E2239 '= <T>(UnicodeString &,const basic_string<T,char_traits<T>,allocator<T> > &)' must be a member function
the error is correct.

An assignment operator shall be implemented by a non-static member function with exactly one parameter (C++03 13.5.3/1).

that is different to operator== which either could be a member or a (static) non-member function.

Roger AlcindorAuthor Commented:
Thanks for your comments,

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