Optimize jQuery

Is there a better way to write the below so I don't need 2 on click commands?

$("#lockSelection").click(function() {

        $("#lockSelection").toggle();
        $("#unlockSelection").toggle();

    })
    $("#unlockSelection").click(function() {

        $("#lockSelection").toggle();
        $("#unlockSelection").toggle();

    })

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LVL 12
Nathan RileyFounderAsked:
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Thomas WheelerCommented:
This is strange you should not need it set up like that. Why is there two different id's here can you elaborate on what you are doing.
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Alexandre SimõesManager / Technology SpecialistCommented:
I don't know exactly what you're doing, but you can do this:
$("#lockSelection, #unlockSelection").click(function() {

        $("#lockSelection").toggle();
        $("#unlockSelection").toggle();

    })

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Nathan RileyFounderAuthor Commented:
Here is the HTML, hope that helps.

 <div id="lockSelection" class="text-center" style="margin-top:15px;cursor:pointer;"><i class="fa fa-lock"></i> Lock Selection</div>
                            <div id="unlockSelection" class="text-center" style="margin-top:15px;cursor:pointer;display:none;"><i class="fa fa-unlock"></i> Unlock Selection</div>

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Alexandre SimõesManager / Technology SpecialistCommented:
Ok, so my solution might be the best option.

You can even use the same event handler if you want to do something else other that just show/hide the div's.
Do this by using the :visible selector to evaluate which is actually visible after the toggles.
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