How to make sure the spawned shell script has fully started?

I have the following code snippet which start a Unix command in the background via the SSH session.

        monitorCommand = "nohup " + monitorCommand + " > " + logFile + " &";
        logger.info("Starting TE monitor '{}'", monitorCommand);
        Cli ssh = TE.getNewCli();
        String response = ssh.send(monitorCommand);
        ssh.disconnect();
        pid = Pid.parse(response, "TE monitor");
        setPid(pid, ssh);
        return pid;

Since spawned remote returns the Unix process id instantly as it is running in the background. However, the process does not start fully before the SSH session is closed. I found that the process was abandoned as I could not find the process manually. If I add sleep for 10 seconds before closing the SSH session, I could find the process survive its launching. The reason for its slow starting maybe due to log directory is mounted to several servers. Since this is library code and works for most process launching, I am wondering whether there is a way to delay the pid returning from the Unix to make sure the process is fully started. For the following statement, could it be "blocked" for a while? :-)

String response = ssh.send(monitorCommand);
gs_kanataAsked:
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simon3270Commented:
It might be easier to wrap the monitor command in a separate shell script, then call that script in the foreground.  Pass the monitor script and log file names as parameters:

#!/bin/bash
# Call the monitor script and wait for the logfile to be produced
monscript=$1
logfile=$2

nohup $monscript > $logfile &

count=0
while [ $count -lt 10 ]; do
  if [ -f $logfile ]; then
    break
  fi
  ((count++))
  sleep 1
done
if [ $count -eq 10 ]; then
  echo Could not start process
  exit 1
fi
exit 0

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Then call this with:
monitorCommand = "/path/to/wrapper.sh " + monitorCommand + " " + logFile;

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