Warning if name already exists in database

I'm trying to alert a user if a name already exists in the database.  Something is wrong with this code.  Can someone tell me what it is?  The syntax is wrong in the first line.

    If DCount("*", "Member Table", "MemberFullName = '" & Me.txtMemberFullName & "') > 0 then
        MsgBox "There is already a member in the database with this name.", vbOKOnly
    End If
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Rey Obrero (Capricorn1)Commented:
you are missing a " at the end before the closing parentheses

 If DCount("*", "Member Table", "MemberFullName = '" & Me.txtMemberFullName & "'") > 0 then

and perhaps better enclose the table in brackets if you still receive an error

 If DCount("*", "[Member Table]", "MemberFullName = '" & Me.txtMemberFullName & "'") > 0 then

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
SteveL13Author Commented:
I provided the wrong info.  I actually have to check for a duplicate record using first and last name.  Here is my before update code but the warning is not appearing:  (now what am I doing wrong?)

    If DCount("*", "Member Table", "MemberFirstName = '" & Me.txtMemberFirstName & "' AND MemberLastName = '" & Me.txtMemberLastName & "'") > 0 Then
        MsgBox "There is already a member in the database with this name.", vbOKOnly
    End If
SteveL13Author Commented:
Never mind. It IS working.  Thanks.  I do have another question closely related but I'll post another topic.
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Microsoft Access

From novice to tech pro — start learning today.