converting text written in 1/8th format to numbers.

I have text which has numbers in this format
"SEP15    1032'0    1040'6    1022'4    1029'0    1031'4    -1'2        9290     1032'6       13361       27522"
the  numbers represent fractions in 8th , i.e  1040'6  is actually means 1040 6/8 , which is 1040.75 , and -1'2  is  -1.25
I am having difficulty in writing a function for  converting this before I put them in a pandas dataframe.
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You can use a function based regular expression substitution:

 re.sub(r"(\d+)'(\d+)", lambda m: str(float( + (float(, i)

>>> import re
>>> data = "SEP15    1032'0    1040'6    1022'4    1029'0    1031'4    -1'2   9290     1032'6       13361       27522"
>>> elements = [ re.sub(r"(\d+)'(\d+)", lambda m: str(float( + (float(, i) for i in re.split(r"\s+",data)]
>>> elements
['SEP15', '1032.0', '1040.75', '1022.5', '1029.0', '1031.5', '-1.25', '9290', '1032.75', '13361', '27522']

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Suhas .Senior QA ManagerCommented:
No comment has been added to this question in more than 21 days, so it is now classified as abandoned.

I have recommended this question be closed as follows:

Accept: clockwatcher (https:#a40878411)

If you feel this question should be closed differently, post an objection and the moderators will review all objections and close it as they feel fit. If no one objects, this question will be closed automatically the way described above.

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