SQL, how to get the max date?

hi Expert,

In my table, each "DealID" may have multiple "created on", so I want to pull out the max(created on) for each "DealID". Can you help me on my query? Thanks.

select count(distinct d.dealid) as testdrive,datename(dw, createdon) as datename
  FROM [MakeMyDeal_com].[dbo].[TestDrivelocal] t inner join Mmd_feed..dealview d on t.dealid=d.dealid 
inner join Mmd_feed..dart dt on dt.dealerid=d.dealerid
where cast(d.submittedtimestamp as date)>=@StartDate and cast(d.submittedtimestamp as date)<=@EndDate
and d.dealstatus='sent'
and d.alternatedeal ='no'
and d.manualdeal='no'
group by datename(dw, createdon)
having createdon= max(createdon)

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Guy Hengel [angelIII / a3]Billing EngineerCommented:
Try this.
use testdb
declare @dealdata table(dealid int,createdon date)
insert into @dealdata values(1,dateadd(dd,1,'2002-01-01'))
insert into @dealdata values(1,dateadd(dd,1,'2002-01-08'))
insert into @dealdata values(1,dateadd(dd,1,'2002-01-05'))
insert into @dealdata values(1,dateadd(dd,1,'2002-01-07'))
insert into @dealdata values(2,dateadd(dd,2,'2002-02-01'))
insert into @dealdata values(2,dateadd(dd,2,'2002-02-03'))
insert into @dealdata values(3,dateadd(dd,3,'2002-01-04'))
insert into @dealdata values(3,dateadd(dd,1,'2002-01-08'))

select count(dealid) dealcount,createdon
select dealid,max(createdon) createdon
from @dealdata
group by dealid
) t1
group by createdon

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Microsoft SQL Server

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