IP Subnetting and Supernetting

In the case I have 192.168.25.0/24 and   the request is about adding 10 subnets ,will the new mask be :
192.168.25.0/28 or ?

Thanks
jskfanAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Mohammed KhawajaManager - Infrastructure:  Information TechnologyCommented:
That is correct.  You will have 16 subnets with each subnet accomodating 14 hosts.
0
Russ SuterCommented:
Here's a handy resource for figuring that sort of thing out. I use it all the time because I'm far too lazy to do binary math in my head.

http://www.subnet-calculator.com/
0
JustInCaseCommented:
You will have 16 subnets with each subnet accomodating 14 hosts.
Ain't necessarily so, that depends on user's needs - it is just said 10 subnets.
You should ask number of hosts per subnet since there can be a lot of combinations.
:)
For example : you can also have 8 networks with 14 clients, and 2 networks with 30 clients. Or any other valid combination.
192.168.25.0/28
192.168.25.16/28
192.168.25.32/28
192.168.25.48/28
192.168.25.64/28
192.168.25.80/28
192.168.25.96/28
192.168.25.112/28
192.168.25.128/26
192.168.25.192/26

If you don't get more specific information go with /28 mask for all 10 subnets.
0
Ultimate Tool Kit for Technology Solution Provider

Broken down into practical pointers and step-by-step instructions, the IT Service Excellence Tool Kit delivers expert advice for technology solution providers. Get your free copy now.

jskfanAuthor Commented:
Predrag Jovic

I thought with 10 subnets, you can get 254 hosts by subnet .
Correct ?
0
Mohammed KhawajaManager - Infrastructure:  Information TechnologyCommented:
This is a C class address where each C class is 254 hosts.  When you divide this to smaller subnets, obviously each subnet will have less hosts.  Now if you were using a B class address then you would start with 65534 hosts and then sub-divide that to additional networks.  If you broke this down to 16 subnets then you would end up with each subnet having 4094 hosts.  As an example, 172.16.0.0/16 = 4094 hosts, 172.116.0.0/20 would give following:

172.16.0.0
172.16.16.0
172.16.32.0
172.16.48.0
172.16.64.0
...
172.16.240.0
0
JustInCaseCommented:
You can have 254 host per network, but not if you create subnets from 192.168.25.0/24 network, you can't divide it and still have 254 hosts per subnet.
You can create 192.168.26.0/24 - 192.168.34.0/24 networks and have 10 subnets, but...
Be careful where network start and where networks end.
I like create networks that can easily be summarized.

If you want you can use any private range.
I always prefer A or B class networks for bussines.
If networks need to have 254 hosts per subnet, I guess I would go with some range like (depending on  already existing networks)
172.16.0.0/24
172.16.1.0/24
.
172.16.9.0/24

As Mohammed already wrote summary would be 172.16.0.0/20 (he had typing by mistake 172.116. :) )
and it would cover 172.16.0.0 - 172.16.15.0 networks
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
jskfanAuthor Commented:
I do not us subnetting often
where I get confused is where to add the bits when it come to subnetting and supernetting

ex: 192.168.0.0/24 ...if the request says add 20 subnets , then the closest is 2^5, which means you add 5 bits from the left
it will become 192.168.0.0/29 =192.168.0.0 255.255.255.248

I guess supernetting (reducing subnets in order to add more hosts) is not very common
0
jskfanAuthor Commented:
I will come back to this at later time
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
TCP/IP

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.