XSLT: Prevent empty tags

I'd like to prevent empty tags from being created in my xml output. The input looks like this:
<Answer name="HouseholdDemographics">
		<RptValue>
			<TextValue unans="true"/>
			<TextValue unans="true"/>
			<TextValue unans="true"/>
			<TextValue>Disability within Household</TextValue>
		</RptValue>
</Answer>

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For output, I need this:
<DemographicList>    
    <Demographic>Disability within Household</Demographic>
</DemographicList>

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but I'm getting this:
<DemographicList>
    <Demographic/>
    <Demographic/>
    <Demographic/>
    <Demographic>Disability within Household</Demographic>
</DemographicList>

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My transform code is currently this:
<xsl:element name="DemographicList">
	<xsl:apply-templates select="//Answer[@name='HouseholdDemographics']/RptValue/TextValue"></xsl:apply-templates>
</xsl:element>

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and
<xsl:template match="//Answer[@name='HouseholdDemographics']/RptValue/TextValue">

	<xsl:variable name="getdemogs" select="position()"/>
	<xsl:variable name="householddemog" select="//Answer[@name='HouseholdDemographics']//RptValue/TextValue[$getdemogs]"/>	
	
	<xsl:if test="normalize-space() or normalize-space($getdemogs)">		
			<xsl:element name="Demographic">
				<xsl:value-of select="$householddemog"/>
			</xsl:element>
					
	</xsl:if> 
	
</xsl:template>

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How can I skip those empty tags in my xml output?
chenegarAsked:
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hieloCommented:
Try:
    <xsl:apply-templates select="//Answer[@name='HouseholdDemographics']/RptValue/TextValue[normalize-space(.)!='']" />

    <xsl:template match="//Answer[@name='HouseholdDemographics']/RptValue/TextValue">
    			<xsl:element name="Demographic">
					<xsl:value-of select="."/>
    			</xsl:element>
    </xsl:template>

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chenegarAuthor Commented:
Exactly what I needed! Thank you.
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