sql DateDiff help

I need to show the record that is 24 hours priors of session start. 

CASE WHEN isNULL(s.repost,0) = 1 
		THEN 
			DateDiff(hh,SU.sessionStart,GETDATE()) 
		ELSE 
			datediff(d, getdate(), SU.sessionStart) 
		END
 >= CASE WHEN isNULL(s.repost,0) = 1 
		THEN 
			24
		ELSE 
			3
		END

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erikTsomikSystem Architect, CF programmer Asked:
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Mike EghtebasDatabase and Application DeveloperCommented:
Select f1, f2
From (Select f1, f2,
CASE WHEN isNULL(s.repost,0) = 1 
		THEN 
			DateDiff(hh,SU.sessionStart,GETDATE()) 
		ELSE 
			datediff(d, getdate(), SU.sessionStart) 
		END As DateCriteria
From TableYouHave) As D (f1, f2, DateCriteria)
Where DateCriteria <=24

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PortletPaulEE Topic AdvisorCommented:
I'm sorry but I don't understand the question as the sql in the question make no sense from line 7 onward

Please remember that THE BEST WAY TO ASK  is to provide:

a. sample data
b. the expected result

If we understand the question easily you get an answer faster and you don't need to clarify the question for us.
awking00Information Technology SpecialistCommented:
select ...
where dateadd(d,1,SU.sessionStart) >= getdate()
Vitor MontalvãoMSSQL Senior EngineerCommented:
erikTsomik, do you still need help with this question?
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