PHP Array Copy

Hi Experts,

I know that in most languages, if you $array_copy = $array_original both variables will point to the same element, so if you change something in one, it will changed in another.

I am trying to add an element to my copy with the following code, but I am not seeing my new element 'xyz'.

$books_copy = new ArrayObject($books);
        foreach ($books_copy as $copy){
            $copy['xyz']=TRUE;
        }
        
        echo '<pre>';
        print_r($books_copy);
        echo '</pre><br>';
        
        
        echo '<pre>';
        print_r($books);
        echo '</pre><br>';

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Any help will be greatly appreciated
APD TorontoSoftware DeveloperAsked:
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hieloCommented:
Try adding an &:
foreach ($books_copy as &$copy){
            $copy['xyz']=TRUE;
        }

FYR:
http://php.net/manual/en/control-structures.foreach.php
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Ray PaseurCommented:
Variables and references in PHP are a little different than in other languages.  Here's the story:
http://www.experts-exchange.com/Web_Development/Web_Languages-Standards/PHP/A_12310-PHP-Variables-and-References.html
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