Help with troubleshooting a Bash Shell script : variable not printed

In the script further below (sorry my browser currently can't attach file due to some issue), the line
below (which is supposed to increment/count the number of files scanned) did not output anything
to the logfile  update.log.  What happened?
   echo "$var "files have been checked." >> /opt/avscan/update.log

I insert the line below because for every file the scanner scanned, it output one line that contains
these strings to update.log causing update.log to become too big:
... $scanfile -NC -l=/opt/avscan /tmp/scan |grep -v "libvsapi.so" |grep -v "+-------" |grep -v "             | " |grep -v "been check" >> ...

======================= Shell script to run AV scan ==================================
var=0
for scanfile in `find /* -type f -size -52428800c -print |grep -v ".sock" |grep -v "/cdrom" |grep -v "/boot" |grep -v "/platfo" |grep -v "/proc" |grep -v mnttab |grep -v "/sys" |grep -v "/dev" |grep -v "/net" |grep -v ".dbf" |grep -v ".arc" |grep -v ".lock" |grep -v ".ctl" |grep -v ".rdo" |grep -v "racle" |grep -v "ysql" |grep -v sulog |grep -v syslog |grep -v messages `; do
    ((var=var+1))
    cd /opt/avscan; nice ./vscan -p=/opt/avscan $scanfile -NC -l=/opt/avscan /tmp/scan |grep -v "libvsapi.so" |grep -v "+-------" |grep -v "             | " |grep -v "been check" >> /opt/avscan/update.log 2>> update.log
done
echo "$var "files have been checked." >> /opt/avscan/update.log
echo "Scan completed on " `date` >> /opt/avscan/update.log
echo "===================" >> /opt/avscan/update.log