How to count a special character in a string with window batch?
Have a string like str=C:\a\b\c\dd\t.txt
Don't know how deep the directory is. How to count how many slashes?
I have no problem to count any char, but the \ is a bit different. Please any guru shed some light on it?
Don't know how deep the directory is. How to count how many slashes?
I have no problem to count any char, but the \ is a bit different. Please any guru shed some light on it?
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This should do the trick:
@echo off
setlocal enabledelayedexpansion
set str=C:\a\b\c\dd\t.txt
call :GetCharCount BackslashCount "%str%" "\"
echo Backslashes found: %BackslashCount%
REM ***** Only functions below this line *****
goto :eof
:GetCharCount <Variable> <string> <Char>
setlocal
set String=%~2
set /a i = 0
set /a CharCount = 0
:GetCharCountLoop
set Char=!String:~%i%,1!
if not "%Char%"=="" (
if /i "%Char%"=="%~3" (set /a CharCount += 1)
set /a i+= 1
goto GetCharCountLoop
)
endlocal&set %~1=%CharCount%
goto :eof
No points for me on this one, but I sometimes use a FOR /L for this one oBdA to avoid GOTO. I really don't like those because they have to read each line of the script from the top to find the label. I tend to use EXIT /B rather than GOTO :EOF for that reason, although I have no sure way of knowing if GOTO is smart enough to handle :EOF special and fast.
I know we think of things a little differently from time to time, I enjoy that about reading your posts. I decided to give up the SETLOCAL in the sub (even though I like that!) and instead directly access the result variable in the loop adding to it real time. As a result I had to clear out the one variable needed by the sub on exit. Anyway, just wanted to share a slightly different approach, but you already provided a viable approach, this was more for tinkering for me.
I know we think of things a little differently from time to time, I enjoy that about reading your posts. I decided to give up the SETLOCAL in the sub (even though I like that!) and instead directly access the result variable in the loop adding to it real time. As a result I had to clear out the one variable needed by the sub on exit. Anyway, just wanted to share a slightly different approach, but you already provided a viable approach, this was more for tinkering for me.
:GetCharCount <Variable> <string> <Char>
set _S=%~2
set /a %~1 = 0
for /L %%i in (0,1,10000) do (
if "!_S:~%%i,1!"=="" (set "_S=" & exit /b)
if /i "!_S:~%%i,1!"=="%~3" set /a %~1 += 1
)
set "_S="
exit /b
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