regarding invoice calculation

I have a clause where
If the single largest invoice is greater than 3 times the average invoices disregard this invoice from the calculation for the recommended loan.
This is what I am using but doesn't seem to work, pls give any suggestions you have

HAVING Max(DISTINCT i.invoice_amt)< 3 *(Sum(DISTINCT i.invoice_amt) / Count(DISTINCT i.invoice_no))
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sqlcuriousAuthor Commented:
here is the actual query, thanks.
I am making the above change at the cte - ctecustfuncomic
PortletPaulEE Topic AdvisorCommented:
Be very cautious of SUM(distinct ...)

This could be a quite misleading calculation depending on the data.

Can you please provide sample data and expected result from that data?
ste5anSenior DeveloperCommented:
Paul is right about DISTINCT, especially as a customer may have three invoices with the same amount but different invoice numbers. This would lead to 1/3 of the real average.

Just use the average:

HAVING MAX(i.invoice_amt) < 3 * AVG(i.invoice_amt)

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Scott PletcherSenior DBACommented:
You say "disregard this invoice", but HAVING will discard the entire GROUPed result row, not just the individual row that has the too-large amount.  You need a WHERE clause to exclude a single row.  Thus, you'd have to get the average first, then use it to exclude individual rows that exceeded 3 times that.
Mayank GairolaSr. Application Support Engg.Commented:
You can also declare a separate variable to simply store 3 * AVG(i.invoice_amt) and then use it accordingly.
PortletPaulEE Topic AdvisorCommented:
For this small example:
    ([ID] int, [invoice_amt] decimal(12,3))
    ([ID], [invoice_amt])
    (1, 12),
    (2, 79),
    (3, 14),
    (4, 6),
    (5, 6),
    (6, 6),
    (7, 6),
    (8, 6),
    (9, 6),
    (10, 6)

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The following query, which uses AVG(...) OVER() so that the average is available for every row, will filter out invoice values grater than 3 times the average.
from (
  select *, AVG(invoice_amt) OVER() as avg_inv
  from YourTable
  ) as i
where invoice_amt < (3* avg_inv)

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The result is, note that ID 2 ($79) is NOT listed
| ID | invoice_amt | avg_inv |
|  1 |          12 |    14.7 |
|  3 |          14 |    14.7 |
|  4 |           6 |    14.7 |
|  5 |           6 |    14.7 |
|  6 |           6 |    14.7 |
|  7 |           6 |    14.7 |
|  8 |           6 |    14.7 |
|  9 |           6 |    14.7 |
| 10 |           6 |    14.7 |

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sqlcuriousAuthor Commented:
I've requested that this question be closed as follows:

Accepted answer: 0 points for sqlcurious's comment #a40913247
Assisted answer: 250 points for ScottPletcher's comment #a40913588
Assisted answer: 250 points for PortletPaul's comment #a40914605

for the following reason:

PortletPaulEE Topic AdvisorCommented:
This does not appear to be an reasonable closure

comment #a40913247 offers no solution whatsoever and should not be the accepted solution
sqlcuriousAuthor Commented:
Thanks a lot for all your responses, sorry my requirement changed and I had to complete everything in a hurry and travel so did not get a chance to respond. The change in requirement was that: I had to only delete that one invoice that was >3Xavg invoice, if there were multiple I do nothing. If a customer has only one outlier invoice I had to change that. So, what I did below worked, but since all of you helped me with the earlier question I will definitely assign points for all.
 SELECT Customer_No,COUNT(*) total, max(invoice_amt) HighestInvoice
                        INTO #base3
                        FROM #base2
                        GROUP BY Customer_No

                    DELETE a
                       FROM #custfuncomic a
                       inner join #base2 b
                       on a.customer_no =b.Customer_No
                       AND a.Invoice_No=b.Invoice_No
                       INNER JOIN #base3 c
                       ON a.Customer_No=c.Customer_No
sqlcuriousAuthor Commented:
Thanks again for all your help.
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Microsoft SQL Server 2008

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