Access - Separate delimited field with comma or dot

The following statements work if the name field only is separated by a comma, but I have found instances where it is separated by a dot as well.

FName = Left([First Name], InStr([First Name], ",")-1)
LName = Right([First Name], Len([First Name]) - InstrRev([First Name], ","))

I have tried to change the "," to be ",",".",""))

Without success.

I also can run this, followed by a separate replace query for the dot, but I am wondering if there is an easier way.

Thank you
exp vgAsked:
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MacroShadowCommented:
You cannot add whichever arguments you want, a function accepts very specific arguments.

If delimited with comma
FName = Left([First Name], InStr([First Name], ",")-1)
LName = Right([First Name], Len([First Name]) - InstrRev([First Name], ","))

If delimited with period
FName = Left([First Name], InStr([First Name], ".")-1)
LName = Right([First Name], Len([First Name]) - InstrRev([First Name], "."))

You will have to test for period or comma and then apply the proper version.
    If InStr([First Name], ",") > 0 Then
        FName = Left([First Name], InStr([First Name], ",") - 1)
        LName = Right([First Name], Len([First Name]) - InStrRev([First Name], ","))
    ElseIf InStr([First Name], ".") > 0 Then
        FName = Left([First Name], InStr([First Name], ".") - 1)
        LName = Right([First Name], Len([First Name]) - InStrRev([First Name], "."))
    End If

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0
IrogSintaCommented:
You can incorporate the Replace function into your InStr function.

FName = Left([First Name], InStr(Replace([First Name],".",","), ",")-1)
LName = Right([First Name], Len([First Name]) - InstrRev(Replace([First Name],".",","), ","))

Open in new window

Ron
1

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exp vgAuthor Commented:
Let me please give these a try.

Thank you both.
0
aikimarkCommented:
Please post examples of names in your database table and how they should be parsed
0
exp vgAuthor Commented:
Thank you.
0
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