Do I need to further validate an int variable return to my from an api?

Hi, I'm using VS2013, C# and asp.net web form
I use Server.HtmlEncode for all the strings type of variable that I got back from calling 3rd party api.  What if the return type if int, can I just count on C# being strong type and would take care of that or do I need to do further validation and how?  
Thank you.
lapuccaAsked:
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Daniel Van Der WerkenIndependent ConsultantCommented:
It would help if we had a little of your code to see how the return is handled.

Short answer: I don't know. Long answer: Here are some things you can do:

object myMostExcellentInteger = 5;
int myInteger = int.MinValue;

if (int.TryParse(myMostExcellentInteger.ToString(), out myInteger))
{
     // Run some excellent code
}

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David Johnson, CD, MVPOwnerCommented:
Enter an Integer
a
Not a Number
Conversion from string "a" to type 'Integer' is not valid.
This is VB but you have to validate all user input.
Imports System
Module Module1
    Sub Main()
        Dim i As Integer
        Console.WriteLine("Enter an Integer")
        Try
            i = Console.ReadLine()
            Console.WriteLine(i)
        Catch ex As Exception
            Console.WriteLine("Not a Number" & vbCrLf & ex.Message)
        End Try
        Console.ReadLine()
    End Sub
End Module

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lapuccaAuthor Commented:
The 3rd party returns an object that I instantiated.  All values returned are stored in this object's property.  I think your example code is good enough.  But my question is also that if this property type is of "int" type then do I still need to check using your example?  I mean, C# is strong type so wouldn't it already throw an exception if I'm getting non-integer or script embedded value in an int property field?
Daniel Van Der WerkenIndependent ConsultantCommented:
I think that's what David Johnson is showing you. If the value returned isn't an integer, then you'll get an exception. Make sure you handle the exception, though.
lapuccaAuthor Commented:
Not exactly the same but okay.  Thank you both.
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