Error converting data type nvarchar to numeric

hi Experts,

trying to insert a textbox value which is formatted 00.00 into a decimal column in sql - getting the title error

the textbox is as shown below:

<asp:TextBox CssClass="textbox" ID="TxtDurationDecimal" onblur="if(this.value=='')this.value=this.defaultValue;" value="00.00"
                                                    onfocus="if(this.value==this.defaultValue)this.value='';" runat="server" ReadOnly="true" Width="70"></asp:TextBox>

the sql is in c# code behind with the following parameter :

cmd.Parameters.AddWithValue("@otDurationDecimal", TxtDurationDecimal.Text);
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cmd.Parameters.AddWithValue("@otDurationDecimal", Convert.ToDecimal(TxtDurationDecimal.Text));
forstersAuthor Commented:
I now get  'Input string was not in a correct format'
forstersAuthor Commented:
The destination column is Decimal(10,2) if that helps...
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Prakash SamariyaIT ProfessionalCommented:
You could try below:
cmd.Parameters.AddWithValue("@otDurationDecimal", Math.Round(Convert.ToDecimal(TxtDurationDecimal.Text), 2));
Does the field have the possibility of spaces, etc?
or 10.25[space]
will be considered a non number.
If there is the possibility of user input, then it must be filtered in all sorts of ways.  Can they enter ABC? or " 10.25 " with spaces? If so at least Trim it first.


If not please debug and check the value on that line in txtDurationDecimal. in a way that will show you any hidden chars.
forstersAuthor Commented:
Thanks both,

I tried cmd.Parameters.AddWithValue("@otDurationDecimal", Math.Round(Convert.ToDecimal(TxtDurationDecimal.Text), 2));
but still get  'Input string was not in a correct format'
The value in TxtDurationDecimal is not user input it's generated by a JavaScript function - the below should demonstrate (duration is a period of time in the format hh:mm) :
var hoursdecimal = "";
                var hoursrounded = "";
                if (duration.split(':')[1] >= '00' && duration.split(':')[1] <= '14') {
                    hoursdecimal = duration.split(':')[0] + ".00";
                    hoursrounded = duration.split(':')[0] + ":00";

                if (duration.split(':')[1] >= '15' && duration.split(':')[1] <= '29') {
                    hoursdecimal = duration.split(':')[0] + ".25";
                    hoursrounded = duration.split(':')[0] + ":15";

                if (duration.split(':')[1] >= '30' && duration.split(':')[1] <= '44') {
                    hoursdecimal = duration.split(':')[0] + ".50";
                    hoursrounded = duration.split(':')[0] + ":30";

                if (duration.split(':')[1] >= '45' && duration.split(':')[1] <= '59') {
                    hoursdecimal = duration.split(':')[0] + ".75";
                    hoursrounded = duration.split(':')[0] + ":45";

                document.getElementById('<%=TxtDuration.ClientID%>').value = duration;
                document.getElementById('<%=TxtDurationRounded.ClientID%>').value = hoursrounded;
                document.getElementById('<%=TxtDurationDecimal.ClientID%>').value = hoursdecimal;
Prakash SamariyaIT ProfessionalCommented:

Could you check whether "TxtDurationDecimal" is getting value of it is empty!?

Or you can try below line:
 cmd.Parameters.Add("@otDurationDecimal", SqlDbType.Decimal).Value = Math.Round(Convert.ToDecimal(TxtDurationDecimal.Text), 2);
My suggestion would be to output the actual value from that function to see if it IS what you expect. Strange things can happen. Always debug by checking the output instead of doggedly assuming all is right and it "should work."  I've thought that many times and found by outputting that it wasn't doing what I expected.  You could do a Decimal.Tryparse(value) and see if it thinks it is a decimal and if not, output and error message, showing the value with "" around it so if it has spaces or something is wrong you can see them.

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