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Convert .txt file to .csv file with single quotations

Hi All,

I'm using the following .bat file to convert a .txt file to a .csv file

@echo off
setlocal enabledelayedexpansion

for /f "tokens=*" %%a in ('type "%~1"') do (
   set line=%%a
   echo "!line:|=","!">>"%~2"
)

However my output file is coming out like this

"999859","0000000000000000000000000","PATIENT NOT FOUND"
"999380","0000000000000000000000000","PATIENT NOT FOUND"

When i need it to be like this, essentially replacing the surrounding double quotes with single quotes.

'999859','0000000000000000000000000','PATIENT NOT FOUND'
'999380','0000000000000000000000000','PATIENT NOT FOUND'

Is there any way to modify the .bat file script to accomplish this? Possibly doing a find and replace on the output file?

Thanks for the assistance!

Just change the script to use single quotes instead of double quotes:

@echo off
setlocal enabledelayedexpansion

for /f "tokens=*" %%a in ('type "%~1"') do (
   set line=%%a
   echo '!line:|=','!'>>"%~2"
)

ASKER

I get the following error when i try to run the .bat file from a cmd prompt

C:\Users\djl4616\Desktop>CONVERT test.txt test.csv
''' is not recognized as an internal or external command,
operable program or batch file.

It still creates an output (test.csv) file but it is blank

ASKER CERTIFIED SOLUTION

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ASKER

That worked beautifully! Thank You!

Since you know there will be three fields, a slightly simpler approach could be:

@echo off
for /f "tokens=1-3 delims=|" %%a in ('type "%~1"') do echo '%%~a','%%~b','%%~c'>>"%~2"

~bp