Recognizing a value instead of the formula

EE Pros,

I have a formula in Cell V70, that reads =If(U70="","",VLOOKUP(C13,$W37:$X41,2FALSE))

Here's the problem.  There is a formula in cell U70 that determines either a number or a blank based on another IF Statement in U70:


If the cell is shows BLANK, although there is a formula calculating the BLANK result in the cell the result produces a #Value! instead of a Blank or Value such as -0-.  

How do I get the formula in cell U70 to look at the result of the formula in V70 INSTEAD of producing an error?

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Could you send a dummy?

Ryan ChongBusiness Systems Analyst , ex-Senior Application EngineerCommented:
quick try... use IFERROR to check for a formula error

=IFERROR(  If(U70="","",VLOOKUP(C13,$W37:$X41,2FALSE)) , V70)

Open in new window

IFERROR function
Bright01Author Commented:
Ryan,  I was in the middle of putting together an example for Rgonzo when your idea came in.  I tested it actually now does not return a #Value result.  

One question, if I wanted to add a multiplier onto the formula where would I put it in?


I want to multiply the result from the VLookup by a number in cell $V$61. Where in this formula would I put that?

=IFERROR(  If(U70="","",VLOOKUP(C13,$W37:$X41,2FALSE)) , V70)
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pls try

=IFERROR(  If(U70="","",VLOOKUP(C13,$W37:$X41,2,FALSE))*$V$61, V70)
Ryan ChongBusiness Systems Analyst , ex-Senior Application EngineerCommented:

=IFERROR(  If(U70="","",VLOOKUP(C13,$W37:$X41,2  ,  FALSE) *  $V$61   ) , V70)

see if this works?

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Bright01Author Commented:
I tried both solutions on adding the additional multiplication.  Ryan, your solution worked based on where the parentheses was placed.

Thank you both!

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