default initialisation of c++ class member variables

Is it to be expected when declaring a new class that has variables, that the variables will be initialised in a consistent fashion when an instance is created using the same compiler ?

For example :
typedef class MyClass
{
   private:
   bool v1;
   int n;
   public:
    MyClass(){};
    ~MyClass(){};
}MyClass;

MyClass *c;

c = new MyClass();

is c->v1 false, true or undefined ?
LVL 2
Roger AlcindorAsked:
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ZoppoCommented:
Hi alcindor,

members of 'native' types (like numbers, bools, pointers) are not initialized by default, so their value is undefined.

Good practise is to initialize those member in an initialization list as i.e shown at https://en.wikipedia.org/wiki/Initialization_%28programming%29#Initializer_list

Members which are class instances are initialized and their default constructor is called.

Hope that helps,

ZOPPO
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Roger AlcindorAuthor Commented:
Thanks for confirming what I am experiencing is to be expected.

Roger
0
evilrixSenior Software Engineer (Avast)Commented:
In C++ you don't need to use the old C way of typedefing classes and structs. Not only is it messy it's also confusing. Just do this...

class MyClass
{
public:
};

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