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Sql Syntax for a replacment
I have never done a mass update to replace records (newbie) in a table so I am looking for some help with the syntax which I'm sure is easy.
I have a table called Parts. In that table there I have a field name called femail. I have records in that field name for email addresses. So records do not require an email address so they are null values.
For the records they contain multiple email addresses in that field which are all the same. So for example:
Femail
test1@test.com; test2@test.com
So my question is I want to do a mass replacment for the test1@test.com email and replace all of those records with JohnDoe@test.com
So the end result would be where test1@test.com was it should now show:
JohnDoe@test.com; test2@test.com
How would I accomplish this?
I have a table called Parts. In that table there I have a field name called femail. I have records in that field name for email addresses. So records do not require an email address so they are null values.
For the records they contain multiple email addresses in that field which are all the same. So for example:
Femail
test1@test.com; test2@test.com
So my question is I want to do a mass replacment for the test1@test.com email and replace all of those records with JohnDoe@test.com
So the end result would be where test1@test.com was it should now show:
JohnDoe@test.com; test2@test.com
How would I accomplish this?
Do more with
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UPDATE Parts
SET femail = REPLACE(femail,'test1@test.com','JohnDoe@test.com')
WHERE femail LIKE 'test1@test.com'
WHERE femail LIKE 'test1@test.com%' --<< nb: the percent sign
if the column femail STARTS with test1@test.com than that where clause will work
but:
WHERE femail LIKE '%test1@test.com%'
if the column femail CONTAINS test1@test.com than that where clause will work (but will be slower)
{+edit}
it is usually prudent to use a select query before trialing an update query
e.g.
select *
from parts
WHERE femail LIKE 'test1@test.com%' --<< nb: the percent sign
so you can assess if the filter is getting the right rows.
if the column femail STARTS with test1@test.com than that where clause will work
but:
WHERE femail LIKE '%test1@test.com%'
if the column femail CONTAINS test1@test.com than that where clause will work (but will be slower)
{+edit}
it is usually prudent to use a select query before trialing an update query
e.g.
select *
from parts
WHERE femail LIKE 'test1@test.com%' --<< nb: the percent sign
so you can assess if the filter is getting the right rows.
Thanks Paul. I forgot to add the percentages:
UPDATE Parts
SET femail = REPLACE(femail,'test1@test.com','JohnDoe@test.com')
WHERE femail LIKE '%test1@test.com%'
--it is a very specific replace " the test1@test.com "
UPDATE Parts
SET femail = REPLACE(femail,'test1@test
WHERE femail ='test1@test.com'
also read
"REPLACE"
https://msdn.microsoft.com/en-us/library/ms186862.aspx
UPDATE Parts
SET femail = REPLACE(femail,'test1@test
WHERE femail ='test1@test.com'
also read
"REPLACE"
https://msdn.microsoft.com/en-us/library/ms186862.aspx
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