achive a distinct date

hi all
how to achive a distinct with order a char as a date


select  distinct(fecha) from cheque order by convert (datetime, fecha,103) desc
ErnestoAsked:
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lcohanDatabase AnalystCommented:
assuming I understand correctly and fecha is a date(time) stored as (var)char datatype that you want to archive only distinct values and in descending order then the following statement should do it:

select  distinct(convert(datetime, fecha,103)) from cheque order by convert (datetime, fecha,103) desc;

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ErnestoAuthor Commented:
Thats, it!!
regards
PortletPaulEE Topic AdvisorCommented:
PLEASE note that distinct is NOT a function

select distinct(fecha) from ...  INCORRECT. Those parentheses are simply ignored

select distinct fecha from ...  CORRECT

SELECT has 2 options:
1. SELECT ALL   (ALL is the default and you do not need to include it, so it is almost always absent)
2. SELECT DISTINCT

& If using SELECT DISTINCT then ALL COLUMNS are considered, not just any column you place in parentheses and those parentheses will just be ignored.

Here's an alternative approach that avoids using varchars

select distinct
       cast(fecha as date) as fecha
from cheque
order by cast(fecha as date) DESC
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