PHP array formatting

I have the following PHP array

JobNo: 15-001:001
TaskNo: 15-001:001
Hours: 2

JobNo: 15-002:002
TaskNo: 15-002:002
Hours: 3

and so on.  I want to convert the values in the JobNo field to only keep everything left of the colon (ie 15-001) and for the TaskNo field only keep everything right of the colon (ie 001).  The resulting array would be:

JobNo: 15-001
TaskNo: 001
Hours: 2

JobNo: 15-002
TaskNo: 002
Hours: 3

Current array is in PHP and would like the conversion to happen on the PHP side.  Thanks!
MrBeedgeAsked:
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Dave BaldwinFixer of ProblemsCommented:
Something like this.  The numbers represent the positions in the sub-arrays.
foreach($array as $val) {
$JobNo = explode(':',$val[0]);
echo $JobNo[0];
$TaskNo = explode(':',$val[1]);
echo $TaskNo[1];
echo $val[2];

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More info: http://php.net/manual/en/control-structures.foreach.php
Dan CraciunIT ConsultantCommented:
Don't you need an "&" to modify the array inside the loop?

foreach ($yourarray as &$row){
  $job = explode(":", $row["JobNo"]);
  $row["JobNo"] = $job[0];
  $task = explode(":", $row["TaskNo"]);
  $row["TaskNo"] = $task[0];
}
unset($row);

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HTH,
Dan
Marco GasiFreelancerCommented:
See if this makes sense to you:
$jobs = array(
		array(
				"JobNo" => "15-001:001",
				"TaskNo" => "15-001:001",
				"Hours" => "2"
		),
		array(
				"JobNo" => "15-002:002",
				"TaskNo" => "15-002:002",
				"Hours" => "3"
		)
);

$final_jpbs = array();
foreach($jobs as $job)
{
//	$final_jobs[] = array();
	$values = explode(':', $job['JobNo']);
	$final_jobs[] = array(
			"JobNo" => $values[0],
			"TaskNo" => $values[1],
			"Hours" => $job['Hours']
	);
}
echo "<pre>";
var_dump($final_jobs);
echo "</pre>";

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Dan CraciunIT ConsultantCommented:
Yup. Marco is right. I have not read the question properly.
foreach ($yourarray as &$row){
  $job = explode(":", $row["JobNo"]);
  $row["JobNo"] = $job[0];
  $row["TaskNo"] = $job[1];
}
unset($row);

Open in new window

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