Need help with \\n

What does '\\n' mean in this reference?  I am assuming linefeed but I need to be sure.  This is in a SQL query.

REPLACE(CAST(addrlines AS nvarchar(2000)), CHAR(13), '\\n')

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huerita37Asked:
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Brian CroweDatabase AdministratorCommented:
This code is replacing the carriage-return character (CHAR(13)) with a literal newline representation I assume for interpretation by whatever is consuming the address.  Typically a combination of CHAR(10) and CHAR(13) is used to represent CRLF (carriage-return / linefeed)
huerita37Author Commented:
I have only seen \n not \\n.

Does the extra \ mean anything?
Brian CroweDatabase AdministratorCommented:
The first one acts as an escape character so that it doesn't treat "\n" as a new line.  Kind of like doubling up on single-quotes to get one single-quote to show up.

It is inserting the literal string "\n" at the end of the addressline and not the newline represented by \n if that makes sense.

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huerita37Author Commented:
Thank you very much.
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Microsoft SQL Server

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