Oracle - Count oads with duplicated stops in sequence no2

i was asked to pull the same Origin Destination and count of the same table from my previous topic but only when we have duplicates DL that follows in sequence.

Previous topic:

00001 = PK
00002 = DL
00002 = DL
00003 = DL

Since after the PK, 00002 shows 2 times in a row, i need to count it.

If  i see the below scenario, even if i have 2 times 00002 but not one after the other, that would not count.
00001 = PK
00002 = DL
00003 = DL
00002 = DL

The format result would be the same as the previous Query accept that now, it will only count when same DL shows more then once onne after the other, so consecutive.

What do i need to adjust in the query?

This is an example of the table again with the result that i would like to get from the query.
Duplicate DL
Thanks again for your help.
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try this

 SELECT COUNT(DISTINCT dl.load_id) bol_count, pk.location_id from_orgin, dl.location_id to_destination
    FROM (SELECT x.*, MIN(recent_pk) OVER (PARTITION BY load_id, location_id) first_pk
            FROM (SELECT tab1.*,
                         LAST_VALUE(CASE WHEN stop_type = 'PK' THEN stop_num END IGNORE NULLS)
                         LAG(location_id) over(partition by load_id order by stop_num) prev_loc
                    FROM tab1) x
           WHERE stop_type = 'DL' AND location_id = prev_loc) dl,
         (SELECT *
            FROM tab1
           WHERE stop_type = 'PK') pk
   WHERE dl.load_id = pk.load_id AND dl.first_pk = pk.stop_num
GROUP BY pk.location_id, dl.location_id;

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Wilder1626Author Commented:
That looks very good. Thanks again for your help
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