# javascript sort an array by number of occurences

Hi there,
I have an array:
var array = [ 3, 4, 2, 3, 2, 3, 3, 3, 4, 4];
I want to sort it so that it will become [3, 3 ,3, 3, 4, 4, 4, 2, 2]
Thank you.
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Manager / Technology SpecialistCommented:
It's pretty late here but I managed to assemble some code :)
http://jsfiddle.net/AlexCode/azhpgLau/
``````var array = [ 3, 4, 2, 3, 2, 3, 3, 3, 4, 4];

function countsort(array){

var getCount = function(){
var result = {};

for(var i=0; i<array.length; i++){
result[array[i]] = (result[array[i]] ? result[array[i]] : 0) + 1;
}

return result;
}

var calCount = getCount();

var sorted = [];
for(var p in calCount){
sorted.push(calCount[p] + ':' + p);
}

sorted = sorted.sort(function(a,b){
var _a = a.split(':')[0];
var _b = b.split(':')[0];

return _a-_b;
});

var result = '';
for(var k=sorted.length-1; k>=0; k--){
var item = sorted[k].split(':');
result += Array(item[0]*1+1).join(item[1]);
}

return result;
}

console.log(countsort(array));
``````
0
Software engineerCommented:
``````var array = [ 3, 4, 2, 3, 2, 3, 3, 3, 4, 4];
var counts = {};
array.forEach(function(value) {
if(!counts[value]) {
counts[value] = 0;
}
counts[value]++;
});
array.sort(function(a, b) {
return counts[a] < counts[b];
});
console.log(array);
``````
Result:
3,3,3,3,3,4,4,4,2,2
1

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Manager / Technology SpecialistCommented:
Good one @zzynx.
I told myself several times that I shouldn't write code after 3AM :)
0
Software engineerCommented:
I told myself several times that I shouldn't write code after 3AM :)
:-)
0
Author Commented:
Thank you guys!
0
Software engineerCommented:
You're welcome.
Thanx 4 axxepting
0
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