Trouble making a file with the name 20151005_log.txt

Hello Powershell Experts,

I have the following code that returns a date of 20151005:
$ArchiveDate = Get-Date -Format yyyyMMdd

I want to create a file named:  20151005_Log.txt.  I think I would use something like the following, but it is not working:

New-Item -Name '"$ArchiveDate"_log.txt' -Path "$ArchiveFilePath\$ArchiveDate" -ItemType file

What am I doing wrong here?

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Jeremy WeisingerSenior Network Consultant / EngineerCommented:
This should do it:
New-Item -Name "$ArchiveDate`_log.txt" -Path "$ArchiveFilePath\$ArchiveDate" -ItemType file

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Note the backtic to escape the underscore.

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You don't need the name if you provide a full path, and for the log file name, you need a subexpression because the underscore is a legal part of a variable name. The subexpression around $ArchiveFilePath is just there because I like to use it whether it's required or not.
New-Item -Path "$($ArchiveFilePath)\$($ArchiveDate)_log.txt" -ItemType File

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Subexpressions are handy for all kinds of manipulation inside strings; this would work, too, for example:
New-Item -Path "$ArchiveFilePath\$(Get-Date -Format yyyyMMdd)_log.txt" -ItemType File

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ndalmolin_13Author Commented:
Thanks for the quick replies.  Both solutions worked!  Thanks for the info on subexpressions.
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