Oracle Select Where String (sans hyphens) is like String

I need to figure out how to apply a regular expression to a query so that the string passed in is compared, dbData LIKE (%passedInString%), to the string in the database, but where the stings are both devoid of hyphens.

Example of what is in the database: DR-9JPE-P-77-7733
Examples of what might be passed in that would return a match: 7777333, P77, 9JPEP-77, etc.

Is it even possible?  Help me out!  :)  And thanks in advance!

A basic, albeit wrong version, of what I am trying to do:
FROM aTable

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slightwv (䄆 Netminder) Commented:
Given that requirement I would replace all dashes with nothing and do an instr:
select * from table where instr(replace(passedin,'-'),replace(INDATABASE,'-')) > 0;

If there is an index on INDATABASE then it will be ignored.  If so, we can try some alternatives.  Easiest is a function-based index.
brianmfallsAuthor Commented:
So, to be literal, would it look like this?

FROM tableName
WHERE instr(replace('9JPEP-77','-'),replace(columnName,'-')) > 0;

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slightwv (䄆 Netminder) Commented:
Sorry.  I had it backwards.

Try this:
FROM tableName
WHERE instr(replace(columnName,'-'),replace('9JPEP-77','-')) > 0;

Set up a quick test case:
select case when  instr(replace('DR-9JPE-P-77-7733','-'),replace('9JPEP-77','-')) > 0 then 'Found' else 'Not Found' end from dual;

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brianmfallsAuthor Commented:
Perfect.  Thanks!
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