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Help to find mistake. c++

SunnyX
SunnyX asked
on
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Last Modified: 2015-10-28
My output don't much with needed output. In first case, I received 7 instead of 6. Please help me find a bag. How should I change my code to receive correct output. Thx in advance.

// Count Subarrays
//Given an array A1, A2, ..., AN, count the number of subarrays of array A
// which are non - decreasing.
//A subarray A[i, j], where 1 ≤ i ≤ j ≤ N is a sequence of integers
// Ai, Ai + 1, ..., Aj.
//A subarray A[i, j] is non - decreasing if Ai ≤ Ai + 1 ≤ Ai + 2 ≤ ... ≤ Aj.
// You have to count the total number of such subarrays.

//Input
//
//The first line of input contains an integer T denoting the number of test cases.
// The description of T test cases follows.
//The first line of each test case contains a single integer N denoting the size
// of array.
//The second line contains N space - separated integers A1, A2, ..., AN
// denoting the elements of the array.

//Output
//
//For each test case, output in a single line the required answer.
//Constraints
//
//1 ≤ T ≤ 5
//1 ≤ N ≤ 105
//1 ≤ Ai ≤ 109
//Subtasks
//
//Subtask 1 (20 points) : 1 ≤ N ≤ 100
//Subtask 2 (30 points) : 1 ≤ N ≤ 1000
//Subtask 3 (50 points) : Original constraints
//Example
//
//Input :
//2
//4
//1 4 2 3
//1
//5
//
//Output :
//      6
//      1
//      Explanation
//
//      Example case 1.
//
//      All valid subarrays are A[1, 1], A[1, 2], A[2, 2], A[3, 3], A[3, 4], A[4, 4].
//      Note that singleton subarrays are identically non - decreasing.
//      Example case 2.
//
//      Only single subarray A[1, 1] is non - decreasing.

#include <iostream>

using namespace std; 

int main() {
	int t; 
	cin >> t; 
	while (t--) {

		int n, sum = 0; 
		cin >> n; 
		int * arr = new int[n];
		
		for (int i = 0; i < n; i++) {

			cin >> arr[i];
		}


		for (int i = 0; i < n; i++) {
			for (int j = 0; j < n; j++) {

				if (arr[i] == arr[j])
					sum++; 

				if (arr[i] - arr[j] == -1)
					sum++;
			}
		}

		cout << sum << endl; 
	}


	return 0; 
}

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