Split similar letter -SQL query

Hi Experts,

I try to think logically to write this procedure but couldn't think one. I want to the split similar occurrence of the letter from a column. How to do it?

Sample example
column
aaa#!RRR@R 
R#!AR###!

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Required Output
OUTPUT
-aaa-#-RRR-@-R
-R-#-!-A-R-###-!

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SQL GuruAsked:
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Brian CroweDatabase AdministratorCommented:
CREATE FUNCTION SplitString
(
	@String			VARCHAR(MAX),
	@Delimiter		VARCHAR(10) = '-'
)
RETURNS VARCHAR(MAX)
AS
BEGIN

DECLARE @Index		INT		= 1,
	@Char			CHAR(1) = NULL,
	@CharPrev		CHAR(1) = NULL;

WHILE @Index <= LEN(@String)
BEGIN
	SELECT @Char = SUBSTRING(@String, @Index, 1),
		@CharPrev = SUBSTRING(@String, @Index - 1, 1);

	IF @Char <> @CharPrev
	BEGIN
		SELECT @String = STUFF(@String, @Index, 0, @Delimiter);
		SELECT @Index += 1;
	END

	SELECT @Index += 1;
END

RETURN @String
END

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Usage (Just replace the hardcoded string value with your column name:
SELECT dbo.SplitString('aaa#!RRR@R', '-')

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Microsoft SQL Server

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