I am constructing a data table from the records. How to pass specifically the records in the place of the URL. As I understand it is expecting the URL instead of JSON data at line number 12
I created a separate JSON file viz. 'data.json' and replaced it in line number 12, as shown above and it worked, but giving the array 'data.records' in the URL is not working.
Please help
AJAXJSONJavaScriptjQuery
Last Comment
Shaji
8/22/2022 - Mon
Pravin Asar
I think what you are looking is a way to filter JSON result.
You can look at the blog post @, which explains how to use datafilter with jQuery Ajax calls.
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You can look at the blog post @, which explains how to use datafilter with jQuery Ajax calls.
https://community.optimizely.com/t5/Developers/Using-jQuery-ajax-datafilter-to-modify-responses-before-success/td-p/11165