Configuring Jetty parameter port using embedded Jetty

I am using Embedded jetty to run my spring mvc application.
I am running it using
java -DFLOCK_APPS_CONFIG=staging/prod -jar snippet.jar

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Now if the parameter is staging i need to run it on port 11001 and if its on prod i need to run in on 8080.
I am setting port like :
 private ServerConnector connector() {
        ServerConnector connector = new ServerConnector(server);
        return connector;

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Here is my complete main java file :

package org.directi.code;

import org.apache.tomcat.InstanceManager;
import org.apache.tomcat.SimpleInstanceManager;
import org.eclipse.jetty.annotations.ServletContainerInitializersStarter;
import org.eclipse.jetty.apache.jsp.JettyJasperInitializer;
import org.eclipse.jetty.server.Server;
import org.eclipse.jetty.server.ServerConnector;
import org.eclipse.jetty.util.log.JavaUtilLog;
import org.eclipse.jetty.util.log.Log;
import org.eclipse.jetty.webapp.WebAppContext;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

import java.util.ArrayList;
import java.util.List;

public class AppStart {
    private static final Logger LOG = LoggerFactory.getLogger(AppStart.class.getName());
    private int port;
    private Server server;

    public static void main(String[] args) throws Exception {
        Log.setLog(new JavaUtilLog());"robin suri");
        String env = System.getProperty("FLOCK_APPS_CONFIG");
        int port = Integer.parseInt(System.getProperty("PORT"));
        AppStart appStart = new AppStart(port);

    public AppStart(int port) {
        this.port = port;

    public void start() throws Exception {
        server = new Server();
        ServerConnector connector = connector();
        WebAppContext webAppContext = getWebAppContext();

    private ServerConnector connector() {
        ServerConnector connector = new ServerConnector(server);
        return connector;

    private WebAppContext getWebAppContext() throws IOException {
        WebAppContext context = new WebAppContext();
        context.setResourceBase(new ClassPathResource("webapp").getURI().toString());
        context.setAttribute("org.eclipse.jetty.containerInitializers", jspInitializers());
        context.setAttribute(InstanceManager.class.getName(), new SimpleInstanceManager());
        context.addBean(new ServletContainerInitializersStarter(context), true);
        return context;

    private List<ContainerInitializer> jspInitializers() {
        JettyJasperInitializer sci = new JettyJasperInitializer();
        ContainerInitializer initializer = new ContainerInitializer(sci, null);
        List<ContainerInitializer> initializers = new ArrayList<ContainerInitializer>();
        return initializers;

    private ClassLoader getUrlClassLoader() {
        ClassLoader jspClassLoader = new URLClassLoader(new URL[0], this.getClass().getClassLoader());
        return jspClassLoader;

    public void stop() throws Exception {

    public void waitForInterrupt() throws InterruptedException {

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And i am having folder structure liek : resources->properties->prod/staging
I want to put some file there which has port information corresponding to the environment
and then pick the proper port number.
What are ways i can do this ?
I think i will need to create a file having an entry like :
Then read that file and set the proper port number.
Please suggest if there are any better ways to do this ?
Rohit BajajAsked:
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mccarlIT Business Systems Analyst / Software DeveloperCommented:
Something like this...

        String env = System.getProperty("FLOCK_APPS_CONFIG");
        Properties props = new Properties();
        props.load(AppStart.getClass().getResourceAsStream("/properties/" + env + "/"));
        int port = Integer.parseInt(props.getProperty("port"));
        AppStart appStart = new AppStart(port);

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