Sql Server 2008r2 select distinct date from datetime

I have a view that im trying to do a select statement from, the set looks something like this.


ComputerName      Counter                Counter Instance      Value      Time(UTC)
SPITERMINAL1      Free Megabytes      C:                           7272              2015-11-19 00:00:00.000
NAWSRAP033894      Free Megabytes      D:                           3723              2015-11-19 00:03:00.000
NAWSRAP033894      Free Megabytes      C:                           4298              2015-11-19 00:03:00.000
aasldsrv10              Free Megabytes      X:                           -999              2015-11-19 00:03:00.000
aasldsrv10              Free Megabytes      W:                           -999               2015-11-19 00:03:00.000
Solomon              Free Megabytes      F:                           25491      2015-11-19 00:03:00.000
BSCVHOSTDC      Free Megabytes      E:                           40796      2015-11-19 00:03:00.000
BSCVHOSTDC      Free Megabytes      C:                           21859      2015-11-19 00:03:00.000
usccgm-dev              Free Megabytes      C:                           22279      2015-11-19 00:03:00.000
USCCSCANSAFE      Free Megabytes      C:                           2490              2015-11-19 00:00:00.000

What i want is the minimum value for each counter instance  on computername for each day. I am new to SQL any help is greatly appriciated. My current script looks like this:

select top 1000 [ComputerName] As 'Computername'
                           ,[Counter Instance]
                           ,min([Value]) As 'Value'
                           ,(SELECT DISTINCT DATEADD(day, 0, DATEDIFF(day, 0, [Time(UTC)]))) AS [Time(UTC)]
                           from [viewReportMonitorCounterLog]
                 where counter = 'Free megabytes' and [Value] > 1
group by  [ComputerName], [Counter Instance], Value, [Time(UTC)]