# Excel formula to calculate the sum of the products of values in two different columns of qualifying rows.

Hello,

This post has two related questions:

Question #1)
What formula in Excel will display the sum of only those values in a given column which have a value (any value) in the same row of a defined adjacent column?

I am familiar with the =SUMIF() formula which returns the sum of those values in a given column which have a specified value in the same row of an adjacent column as shown in the following screenshots (Fig. 1)

However, suppose you want a similar result but instead of specifying a value in the adjacent column, you want the sum of values which have an adjacent entry regardless of its value as shown here (Fig. 2):

In this case, the formula in cell D13 should display the result 18 since that is the sum (as shown to the side) of the values in column D which have an adjacent entry in column C.

Question #2)
Now, what Excel formula in cell D13 will use the same criteria as previously (ie the presence of some entry in the same row of the adjacent column) but instead of a simple sum, will return the sum of the products of the qualifying values in column D and their corresponding values in column C (Fig. 3)?

In this case as previously, only those rows with entries in column C are included in the calculation but the desired result is the sum of the products of adjacent values in columns C & D, as shown again to the side.

Thanks
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Remote Training and ProgrammingCommented:
here is part 1:
``````=SUMIF(C4:C12,">0",D4:D12)
``````
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Commented:
Take a look at the SUMIFS function.. it's more powerful than SUMIF. You can use SUMIFS to incorparate adjacent cells. In your second example you could use something like "=SUMIFS(....) * SUMIFS(...)", multiplying the sums of the 2 columns instead of adding the products, which will yield the same result.
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Remote Training and ProgrammingCommented:
here is part 2:
``````=SUMPRODUCT((C4:C12>0)*(C4:C12),D4:D12)
``````
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Remote Training and ProgrammingCommented:
did the formulas I posted work for you?
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Older than dirtCommented:
This question has been classified as abandoned and is closed as part of the Cleanup Program. See the recommendation for more details.
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