how to find files using regex

hi experts,
I'm trying to find files using regex. Basically I'm trying to use zipdiff (a diff tool ) to exclude certain files using option --regex

my request is exclude (ignore below files from comparing) below highlighted files. e.g where extension contains <anypath>/<anyfilename>.ext<anysuffix>

path1/path2/file1.ext123
path1/path2/file2.ext456
path1/path2/file3.ext789
path1/path2/path3/path4/file4.ext111
path1/path2/file5.ext222
path1/path2/path3/path4/file6.ext333
enthuguyAsked:
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Dan CraciunIT ConsultantCommented:
.*/.*\.ext.*

HTH,
Dan
enthuguyAuthor Commented:
HI Dan, spot on. that worked thx a lot. :)

one more request, how can I specify another pattern in same regex...basically to exclude two files in single expression pls?

exclude
.*/.*\.ext.*
or
.*/.*\.WSDL.*
Dan CraciunIT ConsultantCommented:
I don't understand. What do you want to exclude? Those 2 patterns will work for any files with an ext or WSDL extension.

If you want to include both file extensions, use this:
.*/.*\.(ext|WSDL).*

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enthuguyAuthor Commented:
I've requested that this question be closed as follows:

Accepted answer: 0 points for enthuguy's comment #a41287784

for the following reason:

Thx Dan that helped
for multiple pattern I used pipe, looks like that worked ...make sense?

e.g '.*/.*\.ext.*|.*/.*\.WSDL.*'
enthuguyAuthor Commented:
sorry, Dan's suggestion worked perfectly for me.
I wrongly selected my comment..apologies
Dan CraciunIT ConsultantCommented:
The pipe is the alternation operator: http://www.regular-expressions.info/alternation.html

You usually use it on the non-common parts of the expressions.
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