<div>
if field is always the same format you can do 
=MID(A1,2,1) 
=MID(A1,5,1) 
=MID(A1,8,1) 
 
Each one in diff cell
</div>

<div>
I wrote a user-defined function (UDF) to split your text and return the numeric values. You use store the UDF in a regular module sheet (just like a macro). As written, the UDF doesn't care how many segments there are coming over from the database. Nor does it care how many letter precede the numbers, or how many digits there are in each number. 
 
Below the code, I show two different ways of using the UDF in worksheet formulas. The sample workbook attached to this Comment shows those formulas in action. 

<pre><code class="code-10 nolinks" id="code-20-41481836-1">Function SplitNumbers(sText As String, sDelimiter As String) As Variant
Dim v As Variant, vResults As Variant, vSplit As Variant
Dim s As String
Dim i As Long
vSplit = Split(sText, sDelimiter)
ReDim vResults(0 To UBound(vSplit))
For Each v In vSplit
 s = StrReverse(v)
 vResults(i) = Val(StrReverse(Val(s) &amp; &quot;&quot;))
 i = i + 1
Next
SplitNumbers = vResults
End Function
</code></pre>
If you want to return all three values at once, select three cells in a row, then array-enter a formula like: 
=SplitNumbers(A1,&quot;:&quot;) 
 
If you want to return the values individually, copy across a formula like: 
=INDEX(SplitNumbers($A1,&quot;:&quot;),COLUMNS($G1:G1)) 
<a href="https://filedb.experts-exchange.com/incoming/2016/02_w09/1083483/GetNumbersQ28929030.xlsm" target="_blank" class="file-inline" title="Sample file showing both ways to retrieve numbers (13 KB)"><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 512 512"><path d="M67.508 468.467c-58.005-58.013-58.016-151.92 0-209.943l225.011-225.04c44.643-44.645 117.279-44.645 161.92 0 44.743 44.749 44.753 117.186 0 161.944l-189.465 189.49c-31.41 31.413-82.518 31.412-113.926.001-31.479-31.482-31.49-82.453 0-113.944L311.51 110.491c4.687-4.687 12.286-4.687 16.972 0l16.967 16.971c4.685 4.686 4.685 12.283 0 16.969L184.983 304.917c-12.724 12.724-12.73 33.328 0 46.058 12.696 12.697 33.356 12.699 46.054-.001l189.465-189.489c25.987-25.989 25.994-68.06.001-94.056-25.931-25.934-68.119-25.932-94.049 0l-225.01 225.039c-39.249 39.252-39.258 102.795-.001 142.057 39.285 39.29 102.885 39.287 142.162-.028A739446.174 739446.174 0 0 1 439.497 238.49c4.686-4.687 12.282-4.684 16.969.004l16.967 16.971c4.685 4.686 4.689 12.279.004 16.965a755654.128 755654.128 0 0 0-195.881 195.996c-58.034 58.092-152.004 58.093-210.048.041z"/></svg>GetNumbersQ28929030.xlsm</a>
</div>

Sample file showing both ways to retrieve numbers

GetNumbersQ28929030.xlsm

Sample file showing both formulas and UDF

<div>
Another UDF. 
Assuming your string is in A1, then try this.... 
In B1 
=ExtractNumber($A1,COLUMNS($B1:B1)) 
and then copy across to three columns. 
 
Pls refer to the attached for more details. 

<pre><code class="code-10 nolinks" id="code-20-41481877-1">Function ExtractNumber(Str As Range, i As Long) As String
Dim RegEx As Object
Dim Match As Object
Set RegEx = CreateObject(&quot;vbscript.regexp&quot;)
With RegEx
 .IgnoreCase = True
 .Pattern = &quot;\d&quot;
 .Global = True
End With
If RegEx.test(Str) = True Then
 Set Match = RegEx.Execute(Str)
 ExtractNumber = Match(i - 1)
Else
 ExtractNumber = &quot;&quot;
End If
End Function
</code></pre>
<a href="https://filedb.experts-exchange.com/incoming/2016/02_w09/1083488/ExtractNumbers.xlsm" target="_blank" class="file-inline" title="ExtractNumbers.xlsm (13 KB)"><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 512 512"><path d="M67.508 468.467c-58.005-58.013-58.016-151.92 0-209.943l225.011-225.04c44.643-44.645 117.279-44.645 161.92 0 44.743 44.749 44.753 117.186 0 161.944l-189.465 189.49c-31.41 31.413-82.518 31.412-113.926.001-31.479-31.482-31.49-82.453 0-113.944L311.51 110.491c4.687-4.687 12.286-4.687 16.972 0l16.967 16.971c4.685 4.686 4.685 12.283 0 16.969L184.983 304.917c-12.724 12.724-12.73 33.328 0 46.058 12.696 12.697 33.356 12.699 46.054-.001l189.465-189.489c25.987-25.989 25.994-68.06.001-94.056-25.931-25.934-68.119-25.932-94.049 0l-225.01 225.039c-39.249 39.252-39.258 102.795-.001 142.057 39.285 39.29 102.885 39.287 142.162-.028A739446.174 739446.174 0 0 1 439.497 238.49c4.686-4.687 12.282-4.684 16.969.004l16.967 16.971c4.685 4.686 4.689 12.279.004 16.965a755654.128 755654.128 0 0 0-195.881 195.996c-58.034 58.092-152.004 58.093-210.048.041z"/></svg>ExtractNumbers.xlsm</a>
</div>

ExtractNumbers.xlsm

<div>
I noticed that my UDF would truncate trailing zeros from the number returned. The formula only solution does not have such a problem. 
 
The fix for the UDF (assuming your database text does not include any decimal points) is shown below. Leading zeros will still be truncated because the result is returned as numbers rather than text. 

<pre><code class="code-10 nolinks" id="code-20-41481882-1">Function SplitNumbers(sText As String, sDelimiter As String) As Variant
Dim vResults As Variant, vSplit As Variant
Dim i As Long
vSplit = Split(sText, sDelimiter)
ReDim vResults(0 To UBound(vSplit))
For i = 0 To UBound(vSplit)
 vResults(i) = Val(StrReverse(CStr(Val(&quot;.&quot; &amp; StrReverse(vSplit(i))))))
Next
SplitNumbers = vResults
End Function
</code></pre>
</div>

<div>
Thank you for both options you provided. That one had stumped me...
</div>

<div>
<div class="content wysiwyg-content">
I have a field coming from a database that contains a string of data like so: 
H1:M4:L5 
H4:M3:L8 
 
I need to split this into three different columns but only the numeric value 
Col1 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Col2 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Col3 
1 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 4 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;5 
4 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 3 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;8 
 
I have tried about 10 different approaches and am getting results, just not usable results. 
 
Any advise would be appreciated.
</div>
</div>

I have a field coming from a database that contains a string of data like so:
H1:M4:L5
H4:M3:L8

I need to split this into three different columns but only the numeric value
Col1             Col2            Col3
1                     4                  5
4                     3                  8

I have tried about 10 different approaches and am getting results, just not usable results.

Any advise would be appreciated.

Formula to Parse numeric text in single field into multiple columns - Excel

Microsoft Excel topics include formulas, formatting, VBA macros and user-defined functions, and everything else related to the spreadsheet user interface, including error messages.