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Your sample workbook does not match the formula you say isn't working. I tried to patch it (the workbook) up, and am using the following formula:<br />
=IFERROR(IF([@ResourceType<wbr />]&lt;&gt;&quot;Salari<wbr />ed/W-2&quot;,&quot;&quot;<wbr />,LOOKUP(2,<wbr />1/(([@Reso<wbr />urce]=Sala<wbr />ryDetail_D<wbr />ata!A:A)*(<wbr />[@Dates]=S<wbr />alaryDetai<wbr />l_Data!C:C<wbr />)),SalaryD<wbr />etail_Data<wbr />!D:D)/12),<wbr />&quot;&quot;)<br />
<br />
If the above formula doesn't work in your real workbook, could you please make a Table where you want the formula to go, and add a worksheet SalaryDetail_Data so I can test the looking up.<br />
<br />
Note that if a name occurs more than once in SalaryDetail_Data, the last salary found will be returned.<br />
<a href="https://filedb.experts-exchange.com/incoming/2016/02_w09/1083747/sample-1Q28929389.xlsm" target="_blank" class="file-inline" title="Your file, patched up with more data, with formula (35 KB)"><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 512 512"><path d="M67.508 468.467c-58.005-58.013-58.016-151.92 0-209.943l225.011-225.04c44.643-44.645 117.279-44.645 161.92 0 44.743 44.749 44.753 117.186 0 161.944l-189.465 189.49c-31.41 31.413-82.518 31.412-113.926.001-31.479-31.482-31.49-82.453 0-113.944L311.51 110.491c4.687-4.687 12.286-4.687 16.972 0l16.967 16.971c4.685 4.686 4.685 12.283 0 16.969L184.983 304.917c-12.724 12.724-12.73 33.328 0 46.058 12.696 12.697 33.356 12.699 46.054-.001l189.465-189.489c25.987-25.989 25.994-68.06.001-94.056-25.931-25.934-68.119-25.932-94.049 0l-225.01 225.039c-39.249 39.252-39.258 102.795-.001 142.057 39.285 39.29 102.885 39.287 142.162-.028A739446.174 739446.174 0 0 1 439.497 238.49c4.686-4.687 12.282-4.684 16.969.004l16.967 16.971c4.685 4.686 4.689 12.279.004 16.965a755654.128 755654.128 0 0 0-195.881 195.996c-58.034 58.092-152.004 58.093-210.048.041z"/></svg>sample-1Q28929389.xlsm</a>
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Your sample workbook does not match the formula you say isn't working. I tried to patch it (the workbook) up, and am using the following formula:
=IFERROR(IF([@ResourceType]<>"Salaried/W-2","",LOOKUP(2,1/(([@Resource]=SalaryDetail_Data!A:A)*([@Dates]=SalaryDetail_Data!C:C)),SalaryDetail_Data!D:D)/12),"")

If the above formula doesn't work in your real workbook, could you please make a Table where you want the formula to go, and add a worksheet SalaryDetail_Data so I can test the looking up.

Note that if a name occurs more than once in SalaryDetail_Data, the last salary found will be returned.
sample-1Q28929389.xlsm [https://filedb.experts-exchange.com/incoming/2016/02_w09/1083747/sample-1Q28929389.xlsm]

Your file, patched up with more data, with formula

sample-1Q28929389.xlsm

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<div class="content wysiwyg-content">
I am looking for the correct syntax to lookup the value of the Salary for certain employees where Resource Type = &quot;Salaried/W-2&quot;<br />
<br />
if the Names match, same date and resource type is correct then return the salary value / 12 months.<br />
this what I have so far.<br />
<br />
=IF([@Resource]=SalaryDeta<wbr />il_Data!A:<wbr />A,IF([@Dat<wbr />es]=Salary<wbr />Detail_Dat<wbr />a!C:C,IF([<wbr />@ResourceT<wbr />ype]=&quot;Sala<wbr />ried/W-2&quot;,<wbr />SalaryDeta<wbr />il!D:D)/12<wbr />))<br />
<br />
What am I missing?<br />
<br />
K<br />
<a href="https://filedb.experts-exchange.com/incoming/2016/02_w09/1083744/sample.xlsm" target="_blank" class="file-inline" title="sample.xlsm (30 KB)"><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 512 512"><path d="M67.508 468.467c-58.005-58.013-58.016-151.92 0-209.943l225.011-225.04c44.643-44.645 117.279-44.645 161.92 0 44.743 44.749 44.753 117.186 0 161.944l-189.465 189.49c-31.41 31.413-82.518 31.412-113.926.001-31.479-31.482-31.49-82.453 0-113.944L311.51 110.491c4.687-4.687 12.286-4.687 16.972 0l16.967 16.971c4.685 4.686 4.685 12.283 0 16.969L184.983 304.917c-12.724 12.724-12.73 33.328 0 46.058 12.696 12.697 33.356 12.699 46.054-.001l189.465-189.489c25.987-25.989 25.994-68.06.001-94.056-25.931-25.934-68.119-25.932-94.049 0l-225.01 225.039c-39.249 39.252-39.258 102.795-.001 142.057 39.285 39.29 102.885 39.287 142.162-.028A739446.174 739446.174 0 0 1 439.497 238.49c4.686-4.687 12.282-4.684 16.969.004l16.967 16.971c4.685 4.686 4.689 12.279.004 16.965a755654.128 755654.128 0 0 0-195.881 195.996c-58.034 58.092-152.004 58.093-210.048.041z"/></svg>sample.xlsm</a>
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sample.xlsm

I am looking for the correct syntax to lookup the value of the Salary for certain employees where Resource Type = "Salaried/W-2"

if the Names match, same date and resource type is correct then return the salary value / 12 months.
this what I have so far.

=IF([@Resource]=SalaryDetail_Data!A:A,IF([@Dates]=SalaryDetail_Data!C:C,IF([@ResourceType]="Salaried/W-2",SalaryDetail!D:D)/12))

What am I missing?

K

Lookup and if statements or index Match on several columns

Microsoft Excel topics include formulas, formatting, VBA macros and user-defined functions, and everything else related to the spreadsheet user interface, including error messages.