C# How to pick Person id from listbox string?

I have listbox which has many rows.
First word in every row is PersonId.
I want pick this Person Id and use it in SQL Query like this: " SELECT * FROM mydatatable WHERE ID = '"+ PersonId+"'.
miksuFinAsked:
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CamilliaCommented:
I think you need to look into SelectedItem

Here are the properties

https://msdn.microsoft.com/en-us/library/system.web.ui.webcontrols.listbox_properties(v=vs.110).aspx
miksuFinAuthor Commented:
This is desktop -application, not web-app.
CamilliaCommented:
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miksuFinAuthor Commented:
I suppose that the code is something like this

int item = listBox1.ValueMember.First;
CamilliaCommented:
SelectedValue didn't work?
miksuFinAuthor Commented:
OR something like that
 int item = Convert.ToInt32(listBox1.ValueMember.First(listBox1.Items));
miksuFinAuthor Commented:
I tried this;  int item = Convert.ToInt32(listBox1.SelectedValue);
, but it didn't work.
miksuFinAuthor Commented:
this works almost:
   int item = Convert.ToInt32(listBox1.SelectedItem.ToString());

It shows wanted row like this : {SelectedItem= "3\t\tSometext\t\tSometext\t\tSometext"}

Problem is how to pick "3" from the string.
miksuFinAuthor Commented:
I tried also this:

  string teksti = listBox1.SelectedItem.ToString();

    int item = Convert.ToInt32(teksti.Substring(0, teksti.IndexOf(" "))); <-- Converting problem!
miksuFinAuthor Commented:
This works:

string teksti = listBox1.SelectedItem.ToString();

    int item = Convert.ToInt32(teksti.Substring(0, teksti.IndexOf("\t\t ")));
CamilliaCommented:
good that you figured  it out.
Chris StanyonWebDevCommented:
An alternative approach is to add objects to your ListBox instead of strings. The SelectedItem property of the ListBox will then contain an object and you can simply get a property:

yourClass item = (yourClass)listbox1.SelectedItem;
int personID = item.PersonId;

Open in new window

You could also override the ToString() method in your class to return the PersonId:

var personId = listbox1.SelectedItem.ToString();

Open in new window

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