Unix, date minus 1, 2 or 3 days (last working day)
I got the next expression that gives me the current date just like i need it (ddmmyyyy) :
$(date "+%d%m%Y")
Today is monday, i need the last working day (friday) so i need $(date "+%d%m%Y") minus 3 days
tomorro i will need $(date "+%d%m%Y") minus 1 day (referring to today)
how should i proceed to get those dates using that expression?
This is my machine OS version:
SunOS 5.9 Generic_Virtual sun4u sparc sun4v
$(date "+%d%m%Y")
Today is monday, i need the last working day (friday) so i need $(date "+%d%m%Y") minus 3 days
tomorro i will need $(date "+%d%m%Y") minus 1 day (referring to today)
how should i proceed to get those dates using that expression?
This is my machine OS version:
SunOS 5.9 Generic_Virtual sun4u sparc sun4v
omarfarid
check the day name of today and if it is Mon then - 3 days else - 1 day
Use the date %s which number of sevo ss since epoch/UNIX timestamp. 1/1/1970 00:00:00 GMT.
You can the subtract the 3*24*3600 and convert it to the display you want.
Must you use she'll, or would a command line using perl work as well?
You can the subtract the 3*24*3600 and convert it to the display you want.
Must you use she'll, or would a command line using perl work as well?
If you have a scripting language, such as PHP, this article shows how to make the calculations, taking into account weekends and holidays. You can adapt the design shown in Practical Application #9.
ASKER
Im using just unix a simple ksh script
check the day name of today and if it is Mon then - 3 days else - 1 day
How do i get -3 days and -1 day?
what function shall i use?
if using $(date "+%d%m%Y") i get 24052016
what expression /function should i write to get 23052015 ??
check the day name of today and if it is Mon then - 3 days else - 1 day
How do i get -3 days and -1 day?
what function shall i use?
if using $(date "+%d%m%Y") i get 24052016
what expression /function should i write to get 23052015 ??
You can use the worded "last friday"
as covered in http://blog.midnightmonk.com/85/bash/bash-date-manipulation.shtml
date --date="Last Friday" +"%d%m%Y"
it will return the date of the prior friday in the format you want..
as covered in http://blog.midnightmonk.com/85/bash/bash-date-manipulation.shtml
date --date="Last Friday" +"%d%m%Y"
it will return the date of the prior friday in the format you want..
to get day name run
date +%A
to subtract, try below command on your system:
date --date="3 days ago" "+%d%m%Y"
otherwise you need to install GNU date on your system.
date +%A
to subtract, try below command on your system:
date --date="3 days ago" "+%d%m%Y"
otherwise you need to install GNU date on your system.
Often gnu date might be installed in /usr/sfw/
Pkginfo -I | grep -i date
To see whether you have the sunfreeware package.
Pkginfo -I | grep -i date
To see whether you have the sunfreeware package.
ASKER
I used the next expression to get exactly the same i was asking for :
date "+%a %d%m%Y" | read dt
dt=$(perl -e 'use POSIX;print strftime "%d%m%Y",localtime time-259200;')
thanks anyway for the answers!!!
date "+%a %d%m%Y" | read dt
dt=$(perl -e 'use POSIX;print strftime "%d%m%Y",localtime time-259200;')
thanks anyway for the answers!!!
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ASKER
i used that expression and it worked so far arnold... i used two different localtime amounts to be substracted, for 1 and 3 days respectively.
Not sure to which expression you refer, the fixed 259200 explicitly means three days ago. If you need the logic to no matter when this runs to reflect the date as last Friday , additional logic is needed to determine today and then adjust the time accordingly.