sumDigits challenge

Try a little harder please

We won't (and are not allowed to) write the code for you.
At least come up with some code you wrote yourself.
Starting from that we can (try to) help you further.

public class SumDigits {

	public static void main(String[] args) {
		// TODO Auto-generated method stub

		/*
		 * 
		 * Given a string, return the sum of the digits 0-9 that appear in the
		 * string, ignoring all other characters. Return 0 if there are no
		 * digits in the string. (Note: Character.isDigit(char) tests if a char
		 * is one of the chars '0', '1', .. '9'. Integer.parseInt(string)
		 * converts a string to an int.)
		 * 
		 * sumDigits("aa1bc2d3") → 6 sumDigits("aa11b33") → 8
		 * sumDigits("Chocolate") → 0
		 */
		System.out.println("i is-->" + sumDigits("aa1bc2d3"));
		System.out.println("i2 is-->" + sumDigits("Chocolate"));

	}

	public static int sumDigits(String str) {

		for (int i = 0; i < str.length() - 1; i++) {
			if (str.charAt(i) =='1')){
				return 1;
		} 
		
		if (str.charAt(i) =='2')){
	return 1;
}

	if(str.charAt(i)=='3')){return 1;
}
	else{
		return 0;
		}
	}


}

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i tried as above but getting lot of errors. i know how to do in my mind not able to put in java language compiler understands. please advise

It's rather clear that returning 1 when you encounter the digit '2' or '3' is wrong and won't work.
You have to return the SUM of all digit characters.
So somewhere you'll have to ADD values and when all are added THEN return the sum.

i will try to sum it.

I pressed control shift F but eclipse refused to format some reason. But i will make sure to format all the time

But i will make sure to format all the time

You should make sure that you/Eclipse don't use <tab> but spaces when indenting.

1. Open Window->Preferences from menu bar.
2. Select Text Editors from tree menu.
3. Uncheck Insert spaces for tabs.

After that, (try to) run Format (Ctrl+Shift+F) again.

it was unchecked already for me as attached
preferances.png

public class SumDigits {

	public static void main(String[] args) {
		// TODO Auto-generated method stub

		/*
		 * 
		 * Given a string, return the sum of the digits 0-9 that appear in the
		 * string, ignoring all other characters. Return 0 if there are no
		 * digits in the string. (Note: Character.isDigit(char) tests if a char
		 * is one of the chars '0', '1', .. '9'. Integer.parseInt(string)
		 * converts a string to an int.)
		 * 
		 * sumDigits("aa1bc2d3") ? 6 sumDigits("aa11b33") ? 8
		 * sumDigits("Chocolate") ? 0
		 */
		System.out.println("i is-->" + sumDigits("aa1bc2d3"));
		System.out.println("i2 is-->" + sumDigits("Chocolate"));

	}

	public static int sumDigits(String str) {

		/*
		 * char[] array = reader.toCharArray(); for (char ch : array) {
		 * System.out.println (ch);
		 */
		/*
		 * for (char ch: str.toCharArray()) {
		 * 
		 * 
		 * 
		 * for (int i = 0; i < str.length() - 1; i++) { if
		 * ((Character.isDigit(ch[i])){ return 1; }
		 */

		// String s = "xyz";
		int sum = 0;
		for (int i = 0; i < str.length(); i++) {
			char c = str.charAt(i);
			if (Character.isDigit(c)) {
				sum = sum + Integer.parseInt(String.valueOf(c));
			}
		}
		return sum;

		// if (str.charAt(i) =='2')){
		// return 1;
		// }
		//
		// if(str.charAt(i)=='3')){return 1;
		// }
		// else{
		// return 0;
		// }
		// }

	}

}

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i passed all

Expected      Run            
sumDigits("aa1bc2d3") → 6      6      OK      
sumDigits("aa11b33") → 8      8      OK      
sumDigits("Chocolate") → 0      0      OK      
sumDigits("5hoco1a1e") → 7      7      OK      
sumDigits("123abc123") → 12      12      OK      
sumDigits("") → 0      0      OK      
sumDigits("Hello") → 0      0      OK      
sumDigits("X1z9b2") → 12      12      OK      
sumDigits("5432a") → 14      14      OK      
other tests
OK