sumNumber challenge

Is this homework, gudii9, or what?

We won't (and are not allowed to) write the code for you.
At least come up with some code you wrote yourself.
Starting from that we can (try to) help you further.

@tel2
it is not a home work. And i am not a student. i wonder what made you to think it is a homework?

Given a string, return the sum of the numbers appearing in the string, ignoring all other characters. A number is a series of 1 or more digit chars in a row. (Note: Character.isDigit(char) tests if a char is one of the chars '0', '1', .. '9'. Integer.parseInt(string) converts a string to an int.)

sumNumbers("abc123xyz") → 123//how 1+2+3 is 123 it should be 6 right??same way others?
sumNumbers("aa11b33") → 44
sumNumbers("7 11") → 18

Hi gudii9,

> "i wonder what made you to think it is a homework?"
Because of the way you ask.

Please tell me:
a) What are you if you are not a student?
b) Why do you want to learn Java?
c) How did you decide on these questions?

Thanks.
tel2

No need to repeat the challenge description. We're grown ups, we can click on a link.
Show us that you can write some lines of Java code...

sumNumbers("abc123xyz") → 123//how 1+2+3 is 123 it should be 6 right??
sumNumbers("aa11b33") → 44//how 1+1+3+3 is 44 it should be 8 right??
sumNumbers("7 11") → 18//how 7+1+1 is 18 it should be 9 right??

please advise

A Number is a sequence of digits
The string "abc123xyz" only contains one number: 123
The string "aa11b33" contains two numbers: 11 and 33, their sum is 44
You got the idea I think.

now i got. let me think how to code

i think i need to 2 for loops to compare each character with rest of charactes. let me think more

public int sumNumbers(String str) {
    int sum=0;
		for(int i = 0; i < str.length(); i++)
		{
		   char c = str.charAt(i);
		   if(Character.isDigit(c)){
			   sum=sum +  Integer.parseInt(String.valueOf(c));
		   }
		}
		return sum;
}

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passes half test

Expected      Run            
sumNumbers("abc123xyz") → 123      6      X      
sumNumbers("aa11b33") → 44      8      X      
sumNumbers("7 11") → 18      9      X      
sumNumbers("Chocolate") → 0      0      OK      
sumNumbers("5hoco1a1e") → 7      7      OK      
sumNumbers("5$$1;;1!!") → 7      7      OK      
sumNumbers("a1234bb11") → 1245      12      X      
sumNumbers("") → 0      0      OK      
sumNumbers("a22bbb3") → 25      7      X      
other tests
X      
Your progress graph for this problem

public class SumNumbers {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		System.out.println("sum is--->" + sumNumbers("7 11"));

	}

	public static int sumNumbers(String str) {
		int sum = 0;
		for (int i = 0; i < str.length(); i++) {

			char c = str.charAt(i);
			if (Character.isDigit(c)) {
				sum = sum + Integer.parseInt(String.valueOf(c));
			} else {

				i = i + 1;
			}

		}
		return sum;
	}

}

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gives worn output
sum is--->8

need to make my solution more universal so that i can move exact distance not 1 all the time

not able to maker it work with 2 for loops.

below passed all tests

public int sumNumbers(String str) {
        int len = str.length();
		  int sum = 0;
		  String tmp = "";
		  
		  for (int i = 0; i < len; i++) {
		    if (Character.isDigit(str.charAt(i))) {
		      if (i < len-1 && Character.isDigit(str.charAt(i+1))) {
		        tmp += str.charAt(i);
		      }
		      else {
		        tmp += str.charAt(i);
		        sum += Integer.parseInt(tmp);
		        tmp = "";
		      }
		        
		    }
		  }
		  
		  return sum;
		}

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public int sumNumbers(String str) {
        int sum = 0;
        for (int i = 0; i < str.length(); i++) {
            if (Character.isDigit(str.charAt(i))) {
                int count = 0;
                for (int j = i; j < str.length(); j++) {
                    if (Character.isDigit(str.charAt(j))) count++;
                    else break;
                }
                sum += Integer.parseInt(str.substring(i, i + count));
                i += count;
            }
        }
        return sum;
}

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above inner for loop why we need to start j=1 rather than j=0 similar to outer for loop(where i started with 0)