mustish1
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2k Power n formula
According to my calculation 2 Power K >= n is 2 Power 6 > = 33 and width = Largest - Smallest / 6 is (629294 - 2666) / 6 --> 104438. On the basis of this number how to i create a range in frequency distribution? need help
Thanks.
Range Frequency Distribution
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Using the 2 Power k ≥n guideline, what is the minimum number of classes that should be used to display the data in a grouped data frequency distribution?
2666, 11485, 14696, 15348, 16180, 19366, 31732, 32460, 33958, 39534, 39743, 47855, 58423, 59484, 60318, 64371, 82392, 90053
96556, 97833, 99866, 108185, 159940, 265193, 359565, 380676, 384028, 385465, 448665, 462846, 601242, 626568, 629294
Thanks.
Range Frequency Distribution
--------------------------
Using the 2 Power k ≥n guideline, what is the minimum number of classes that should be used to display the data in a grouped data frequency distribution?
2666, 11485, 14696, 15348, 16180, 19366, 31732, 32460, 33958, 39534, 39743, 47855, 58423, 59484, 60318, 64371, 82392, 90053
96556, 97833, 99866, 108185, 159940, 265193, 359565, 380676, 384028, 385465, 448665, 462846, 601242, 626568, 629294
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