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Need another set of eyes on accessing variable.

Posted on 2016-07-15
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Last Modified: 2016-07-15
I can't see what's wrong with this (the query is correct and returns 5000+ records).

$SqlString = "select * from comp";
$comp = $conn->query($SqlString);
$row_comp = $comp->fetch_array();
$work = $row_comp['TID'];

$work ends up as "TID"
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Question by:breeze351
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4 Comments
 
LVL 84

Expert Comment

by:Dave Baldwin
ID: 41713328
Looks fine from here.  What do you think it is supposed to do?
http://php.net/manual/en/mysqli-result.fetch-array.php
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Accepted Solution

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Kim Walker earned 2000 total points
ID: 41713337
This would suggest that the value of the column "TID" in the first row of your result is also "TID". Did you upload a CSV file that had a header row? If you did, the first row in your table is that header row.

Other that this, there isn't enough information here to guess. Have you run the query in your database control panel to see what the values are in the first row?
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Author Closing Comment

by:breeze351
ID: 41713357
BINGO!!!!!  Never would have thought of it.
Thanks
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LVL 11

Expert Comment

by:Ovid Burke
ID: 41713366
I tend to agree with Kim. It seems likely that at least one row in tour data contains the column names of your table.
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