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breeze351
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Need another set of eyes on accessing variable.

I can't see what's wrong with this (the query is correct and returns 5000+ records).

$SqlString = "select * from comp";
$comp = $conn->query($SqlString);
$row_comp = $comp->fetch_array();
$work = $row_comp['TID'];

$work ends up as "TID"
PHP

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Last Comment
Ovid Burke

8/22/2022 - Mon
Dave Baldwin

Looks fine from here.  What do you think it is supposed to do?
http://php.net/manual/en/mysqli-result.fetch-array.php
ASKER CERTIFIED SOLUTION
Kim Walker

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breeze351

ASKER
BINGO!!!!!  Never would have thought of it.
Thanks
Ovid Burke

I tend to agree with Kim. It seems likely that at least one row in tour data contains the column names of your table.
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