Excel formula if

Hello,
can you please help,
I'm trying to say, if left of cell like then
=IF(LEFT(AK2,10)="RESIDENCE",AM2+3,IF(LEFT(AK2,11)="RESIDENTIAL",AM2+3,IF(LEFT(AK2,9)="RESIDENT",AM2+3,AM2)))

it seems to work only on exact words.
Example
if the cells was
RESIDENCE_____
RESIDENTIAL ---
RESIDENT yes

formula doesn't work.
thanks
W.E.BAsked:
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Naresh PatelTraderCommented:
Try something like this or post sample Work book.

=IF(ISERROR(FIND("Resident",AK2,1))=TRUE,0,AM2+3)

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Thanks
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W.E.BAuthor Commented:
Thank you, this worked,
=IF(ISERROR(FIND("RESIDENCE",AK2,1))=TRUE,AM2,AM2+3)

how do I add to the formula
RESIDENTIAL
RESIDENT
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Subodh Tiwari (Neeraj)Excel & VBA ExpertCommented:
Does column AK contains some leasing spaces in them?

BTW try this....

=IF(OR(LEFT(TRIM(AK2),8)="RESIDENT",LEFT(TRIM(AK2),9)="RESIDENCE",LEFT(TRIM(AK2),11)="RESIDENTIAL"),AM2+3,AM2+2)

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If that doesn't work for you, please upload a sample workbook with some dummy data.
1

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Subodh Tiwari (Neeraj)Excel & VBA ExpertCommented:
Or you can also try this....

=IF(OR(ISNUMBER(SEARCH({"Residence","Resident","Residential"},AK2))),AM2+3,AM2+2)

Open in new window

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W.E.BAuthor Commented:
thank you very much.
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W.E.BAuthor Commented:
thanks
0
Subodh Tiwari (Neeraj)Excel & VBA ExpertCommented:
You're welcome.
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Naresh PatelTraderCommented:
@Subodh Tiwari (Neeraj)...Thumbs Up ....this is how i learnt .....Thanks
@ Wass_QA  mine formula wont work for your all condition.
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Subodh Tiwari (Neeraj)Excel & VBA ExpertCommented:
@itjockey

Glad you found it helpful. :)
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Rob HensonFinance AnalystCommented:
Don't know if this would have helped but your original formula had incorrect character lengths for two of the options:

LEFT(AK2,10)="RESIDENCE"  but RESIDENCE = 9
LEFT(AK2,11)="RESIDENTIAL" correct as RESIDENTIAL = 11
LEFT(AK2,9)="RESIDENT" but RESIDENT = 8
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