mustish1
asked on
Relative Frequency
Can you please tell me why my answer is wrong? Thanks.
brown?
P(brown) = (Round to four decimal places as needed.) 92+226/993 = 0.320
b. What is the probability that the product manufactured is an HD-99?
P(HD-99)= (Round to four decimal places as needed.) = 48+226+125/ 993= 0.401
c. What is the probability that a product manufactured is an HD-99 and brown?
P(HD-99)= (Round to four decimal places as needed.) = 226 / 993 = 0.227
brown?
P(brown) = (Round to four decimal places as needed.) 92+226/993 = 0.320
b. What is the probability that the product manufactured is an HD-99?
P(HD-99)= (Round to four decimal places as needed.) = 48+226+125/ 993= 0.401
c. What is the probability that a product manufactured is an HD-99 and brown?
P(HD-99)= (Round to four decimal places as needed.) = 226 / 993 = 0.227
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SOLUTION
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I don't get the same result as you for 226/933!
0.2275931520644512 use bankers rounding
0.00005 = 0.2276431 now truncate = 0.2276
0.00005 = 0.2276431 now truncate = 0.2276
ASKER