Solved

# Independent Events

Posted on 2016-07-21

Can you please tell me if these calculations are correct? Thanks.

A restaurant in a fast food franchise has determined that the chance a customer will order a soft drink is 0.95. The probability that a

customer will order a hamburger is 0.68. The probability that a customer will order french fries is 0.59.

a. If a customer places an order, what is the probability that the order will include a soft drink and no fries if these two events are

independent? The probability is : P(soft drink) = 0.95, P(french fries) = 0.59, the complement of f(F) is 0.59

P(s intersection f), intersection of two independent events calls for multiplying each probability

P(s) * P(f) = 0.95 * 0.59 = 0.5605

b. The restaurant has also determined that if a customer orders a hamburger, the probability the customer will order fries is 0.72.

Determine the probability that the order will include a hamburger and fries.

The probability is P(h intersection f) = 0.68 * 0.59 = 0.4012 The two events would not be independent.