Solved

Synchronize upper and lower tabs on a form

Posted on 2016-07-22
5
70 Views
Last Modified: 2016-07-25
I have a tall form in which a user has access to three tabs on top and three corresponding tabs on the bottom.

I'm trying to write javascript\jquery to keep the tabs in sync(active) depending upon which is selected.

So here are my upper tabs:

<ul id="Tabs" class="nav nav-tabs">
        <li class="active"><a href="#pm" data-toggle="tab" id="pmTab">PM</a></li>
        <li><a href="#engineer" data-toggle="tab" id="engineerTab">Engineer</a></li>
        <li><a href="#contractor" data-toggle="tab" id="contractingTab">Contracting</a></li>
    </ul>

<div class="tab-content well"> .....

Open in new window



Here are my lower tabs
...</div>
 <div id="BottomTabs" class="tabbable tabs-below">
            <ul id="TabsBelow" class="nav nav-tabs">
                <li class="active"><a href="#pm" data-toggle="tab" id="pmTabBottom">PM</a></li>
                <li><a href="#engineer" data-toggle="tab" id="engineerTabBottom">Engineer</a></li>
                <li><a href="#contractor" data-toggle="tab" id="contractingTabBottom">Contracting</a></li>
            </ul>
        </div>

Open in new window


Now here are my click events
 function BindTabClickEvents() {
            $('#Tabs a, #TabsBelow a').click(function (e) {
                e.preventDefault();
                
                $(".nav-tabs li").each(function(element) {
                    $(this).removeClass("active");
                });

                $(this).addClass("active");
               

                switch ($(this).html()) {
                    case "PM":
                       
                        if (e.target.id === "pmTab") {
                            $('#pmTabBottom').addClass("active");
                        } else {
                            $('#pmTab').addClass("active");
                        }
                        break;
                    case "Engineer":
                       if (e.target.id === "engineerTab") {
                            $('#engineerTabBottom').addClass("active");
                        } else {
                            $('#engineerTab').addClass("active");
                        }
                        break;
                    case "Contracting":
                        $('#programNameContracting').html($("#ProgramName").val());
                        if (e.target.id === "contractingTab") {
                            $('#contractingTabBottom').addClass("active");
                        } else {
                           $('#contractingTab').addClass("active");
                        }
                        break;
                }

                $(this).tab('show');
            });
        }

Open in new window


The case statement is assigning the "Active" class but the corresponding tab does not look "active". Also, the other tabs seem to be retaining the active class even after I iterate through them and remove it.
0
Comment
Question by:Focker513
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
  • 2
5 Comments
 
LVL 53

Expert Comment

by:Scott Fell, EE MVE
ID: 41725110
Can you create a working sample?  Either a minimal sample page on your own site or recreate on jsbin, jsfiddle or codepen.  

Just as a quick suggestion, on the click event the first thing you can do is make all inactive, then only make the clicked tab active.
0
 

Author Comment

by:Focker513
ID: 41725238
Sorry been pulled into another issue. I will try to update with jsfiddle later. If you look I am iterating through and removing active so you are saying also add inactive? That actually may be what I need to try.

Regardless can't test at the moment but will get back to you. I apologize, thanks for your time.
0
 
LVL 53

Expert Comment

by:Scott Fell, EE MVE
ID: 41725300
Here is a simple example where I remove the class on click, then add to the specific item.
http://jsbin.com/cuzoruceve/edit?html,output
<!DOCTYPE html>
<html>
<head>
<script src="https://code.jquery.com/jquery-2.0.3.js"></script>
  <script>
    $(function(){
       $('ul#top li').on('click',function(){
          $('ul#top li').removeClass('red');
          $(this).addClass('red');
 
          });
  
    });
  </script>
  <style>
    .red{color:Red;}
    .blue{color:Blue;}
  </style>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>JS Bin</title>
</head>
<body>
   <ul id="top">
     <li>one</li>
     <li>two</li>
     <li>three</li>
   </ul>
   <ul id="bottom">
     <li>one</li>
     <li class="blue">two</li>
     <li>three</li>
   </ul>
</body>
</html>

Open in new window

0
 
LVL 49

Accepted Solution

by:
Roonaan earned 500 total points
ID: 41725606
I would go for a setup like this. Instead of matching tabs by "id" I use the "href" to figure out if two tabs have the same target and thus need to be highlighted with the same state.
This will make sure you code does not expands with the number of your tabs, introducing costly maintenance.

 function BindTabClickEvents() {
    var links = $('#Tabs a, #TabsBelow a');
    links.click(function(e) {
        e.preventDefault();
        var linkClicked = $(this).closest('a');
        var target = linkClicked.attr('href');
        links.each(function() {
           if ($(this).attr('href') === target) {
                $(this).addClass('active');
                $(this).closest('li').addClass('active');
           } else {
               $(this).removeClass('active');
               $(this).closest('li').removeClass('active');
           }
        });
        $(this).tab('show');
    });
}

Open in new window


The above code does toggle "active" class on both the <a> as the surrounding <li>. From your code it was unclear which one is needed in the end.

Best

-r-
0
 

Author Closing Comment

by:Focker513
ID: 41727806
awesome worked without issue
0

Featured Post

Application Discovery Service in AWS

In the era of the cloud, customers migrating away from their existing on-premise infrastructure. This requires lots of planning, strategies, and effort to identify their existing resources and determine how best to migrate.  Datacenter migrations happen in four phases -

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

This article discusses how to create an extensible mechanism for linked drop downs.
This article discusses how to implement server side field validation and display customized error messages to the client.
In this tutorial viewers will learn how to embed an audio file in a webpage using HTML5. Ensure your DOCTYPE declaration is set to HTML5: : The declaration should display (CODE) HTML5 is supported by the most recent versions of all major browsers…
Video by: Mark
This lesson goes over how to construct ordered and unordered lists and how to create hyperlinks.
Suggested Courses

636 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question