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how to get fastest lap time and driver iD per race

hello as per title: how to get fastest lap time and driver iD per race

if i run
SELECT * FROM F1database.lapTimes

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 i get

# raceId, driverId, lap, position, time, milliseconds
'841', '20', '1', '1', '1:38.109', '98109'
'841', '20', '2', '1', '1:33.006', '93006'
'843', '20', '3', '1', '1:32.713', '92713'


actual results in attached file  

I would love result of

raceid, fastesttime, driverId

so i 10 races i would get 10 results if 700 races i would get 700 results.....  hope that all makes sense and that you can help
result.csv
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James Murrell
Asked:
James Murrell
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1 Solution
 
PortletPaulCommented:
what is the actual data type of the lap time column?
are all the other columns int (integers)?
what version of MySQL are you using?
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PortletPaulCommented:
for this sample:
CREATE TABLE lapTimes
    (`raceId` int, `driverId` int, `lap` int, `position` int, `time` varchar(12), `milliseconds` int)
;
    
INSERT INTO lapTimes
    (`raceId`, `driverId`, `lap`, `position`, `time`, `milliseconds`)
VALUES
    (841, 20, 1, 1, '1:38.109', 98109),
    (841, 20, 2, 1, '1:33.006', 93006),
    (843, 20, 3, 1, '1:32.713', 92713)

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select
l.*
from lapTimes l
inner join (
        select
              raceId
            , driverId
            , min(milliseconds) milliseconds
        from lapTimes
        group by
              raceId
            , driverId
  ) m on l.raceId = m.raceId and l.driverId = m.driverId
      and l.milliseconds = m.milliseconds
;

| raceId | driverId | lap | position |     time | milliseconds |
|--------|----------|-----|----------|----------|--------------|
|    841 |       20 |   2 |        1 | 1:33.006 |        93006 |
|    843 |       20 |   3 |        1 | 1:32.713 |        92713 |

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select
      raceId
    , driverId
    , sum(milliseconds) / 1000 race_seconds
from lapTimes
group by
      raceId
    , driverId
;
| raceId | driverId | race_seconds |
|--------|----------|--------------|
|    841 |       20 |      191.115 |
|    843 |       20 |       92.713 |

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select
  `time`
, left(`time`,locate(':',`time`)-1) mins
, substr(`time`,locate(':',`time`)+1,2)  secs
, right(`time`, length(`time`) - locate('.',`time`)) hundedths
, milliseconds / 1000
from lapTimes

|     time | mins | secs | hundedths | milliseconds / 1000 |
|----------|------|------|-----------|---------------------|
| 1:38.109 |    1 |   38 |       109 |              98.109 |
| 1:33.006 |    1 |   33 |       006 |              93.006 |
| 1:32.713 |    1 |   32 |       713 |              92.713 |

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1
 
bcnagelCommented:
Paul Maxwell is right: it would be helpful to know data types of your columns and more general information about your environment.

I'm going to assume that your milliseconds column represents the milliseconds elapsed for the lap in question, and I'm going to assume that it is an integer (or other numeric) column. That being the case, does this query give you what you need?

select der.raceId, lt.driverId, der.fastestLap
	from F1database.lapTimes as lt
	join (
		select lt.raceId, min(lt.milliseconds) as fastestLap
			from F1database.lapTimes as lt
			group by lt.raceId
		) der
	on lt.raceId = der.raceId
		and lt.milliseconds = der.fastestLap
	order by lt.raceId

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PortletPaulCommented:
darn, for fastest laptime one ignores the driverid.... oh well
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bcnagelCommented:
Yep, I'm guessing we ignore the driverId, Paul. On the other hand, until we hear back from James we're just making our best guesses as to what he's really looking for. :-)
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James MurrellProduct SpecialistAuthor Commented:
wow thanks, sorry i had to sleep.

i get data from http://ergast.com/mrd/db/ 


I will review these later today.  I am in meetings and will get back to you guys
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James MurrellProduct SpecialistAuthor Commented:
Hello all great answer i will be accepting bcnagel answer as it it the one that makes sense to me: Basically I understand it....


big thanks guys
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James MurrellProduct SpecialistAuthor Commented:
great answer, one i could read and understand.... thanks
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